Binary byte[] buffer to hex byte[] buffer conversion

[Zulik]

Hello,

I might have a bad day today but I have a byte[] buffer holding binary
numbers. Now, I want to convert this to byte[] buffer with hex numbers. Is
there any elegant way of doing that?

Some method like: byte[] bin2hex(byte[]) {}

BRs,
Zulik

[hiwa]

Zulik <zu*****@yahoo. com> wrote in message news:<pa******* *************** ******@yahoo.co m>...

Hello,

I might have a bad day today but I have a byte[] buffer holding binary
numbers. Now, I want to convert this to byte[] buffer with hex numbers. Is
there any elegant way of doing that?

Some method like: byte[] bin2hex(byte[]) {}

BRs,
Zulik

Hex representation of number can't be Java byte type. And whatever the
representation format would be, the value of the number is same. 0x20
is 32 is 00100000.

[GianpieroP]

"Zulik" <zu*****@yahoo. com> ha scritto nel messaggio news:pa******** *************** *****@yahoo.com ...

Some method like: byte[] bin2hex(byte[]) {}

maybe did you intended "String bin2hex(byte[])" ?

if it was so, (Sorry for my english: I'm translating "word to word"
from Italian lang. :-) )
here you are the following code:

public class HexTool {

static private String[] HEX = {"0","1","2","3 ","4","5","6"," 7","8","9","A", "B","C","D","E" ,"F"};

static public String hexify(byte byValue){
int nValue = (int)byValue + 128;
return HEX[nValue/16]+HEX[nValue%16];
}

static public String hexify(byte[] bytes){
String hexed ="";
for(int i = 0; i<bytes.length ; i++){
hexed += hexify(bytes[i])+" ";
}
return hexed;
}
}

Bye,
GianpieroP

[Chris]

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GianpieroP wrote:

"Zulik" <zu*****@yahoo. com> ha scritto nel messaggio
news:pa******** *************** *****@yahoo.com ...

Some method like: byte[] bin2hex(byte[]) {}

maybe did you intended "String bin2hex(byte[])" ?

[snippage of a bin2hex algorithm]

Hi,
Or, even more concise, how about a call to
java.lang.{Inte ger|Long}.toHex String()?

Heh... don't re-invent the wheel :)

- --
Chris
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[GianpieroP]

"Chris" <ch*******@hotm ail.com> ha scritto nel messaggio news:UzfYb.1804 2$Hy3.8786@edtn ps89...

Hi,
Or, even more concise, how about a call to
java.lang.{Inte ger|Long}.toHex String()?

Heh... don't re-invent the wheel :)

Ok! So my class loses one method: "... hexify(byte byValue)" and one member: "HEX".
But my "wheel" is useful again because it presents "String hexify(byte[] byArr)" static method.
However I'm happy if you offers me another existent "wheel" in substitution of my hexify(byte[] ) method.

Bye bye,
GianpieroP

[Chris]

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GianpieroP wrote:

"Chris" <ch*******@hotm ail.com> ha scritto nel messaggio
news:UzfYb.1804 2$Hy3.8786@edtn ps89...

Hi,
Or, even more concise, how about a call to
java.lang.{Inte ger|Long}.toHex String()?

Heh... don't re-invent the wheel :)

Ok! So my class loses one method: "... hexify(byte byValue)" and one
member: "HEX". But my "wheel" is useful again because it presents
"String hexify(byte[] byArr)" static method. However I'm happy if
you offers me another existent "wheel" in substitution of my
hexify(byte[] ) method.

Bye bye,
GianpieroP

Heh... actually, if working with large values, how about:

public static String hexify(byte[] data) {
StringBuffer sb = new StringBuffer();
for (int i = 0; i < data.length; i++) {
sb.append(Integ er.toHexString( ((int) data[i]) & 0xFF));
}
return sb.toString();
}

The use of StringBuffer is the real point I'm making here, since it's
more efficient than repeated String concatenations. Also, since
Integer.toHexSt ring() takes an int, you have to do the casting
oddness to prevent, say, -1 from turning into 0xFFFFFFFF. Other than
that, your method and mine are about the same. So that's my 2-cent
wheel :)

- --
Chris
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