I need to have two different backgrounds, one on the left and one on the
right of the screen, with the main content centered in the browser. This is
the code I have come up with
<table border="0" cellpadding="0" cellspacing="0" width="100%">
<tr>
<td width="49%" background="lef t.gif"><img src="shim.gif" alt=""
height="1" width="1"></td>
<td width="2%" valign="top"> ALL CONTENT </td>
<td width="49%" background="rig ht.gif"><img src="shim.gif" alt=""
height="1" width="1"></td>
</tr>
</table>
This seems to work perfectly, however I'm slighlty unsure as the numbers
don't add up. Say my Content in the middle cell is a 750 pixel wide nested
table, this would obviously mean that the percentage are not as described.
Is there a chance that certain browsers will choke on this code? and maybe
not display the middle cell in the middle of the page? 5 2062
In article <cl**********@n ewsg4.svr.pol.c o.uk>,
"luke" <lu*********@no emailspam.com> wrote: I need to have two different backgrounds, one on the left and one on the right of the screen, with the main content centered in the browser. This is the code I have come up with
<table border="0" cellpadding="0" cellspacing="0" width="100%"> <tr> <td width="49%" background="lef t.gif"><img src="shim.gif" alt="" height="1" width="1"></td> <td width="2%" valign="top"> ALL CONTENT </td> <td width="49%" background="rig ht.gif"><img src="shim.gif" alt="" height="1" width="1"></td> </tr> </table>
This seems to work perfectly, however I'm slighlty unsure as the numbers don't add up. Say my Content in the middle cell is a 750 pixel wide nested table, this would obviously mean that the percentage are not as described. Is there a chance that certain browsers will choke on this code? and maybe not display the middle cell in the middle of the page?
Wait, you mean, all that when this will do?
CSS:
body {
color: #000;
background: url("750pxwideg reenblock.png") #0000cc repeat-y;
text-align: center;
}
#content {
width: 750px;
margin: 0 auto;
text-align: left;
color: #000;
background: green;
}
HTML:
<body>
<div id="content">
Whatever content you have.
</div>
</body>
--
Kris
<kr*******@xs4a ll.netherlands> (nl)
"Kris" <kr*******@xs4a ll.netherlands> wrote in message
news:kr******** *************** ******@news1.ne ws.xs4all.nl... Wait, you mean, all that when this will do?
Wait, I think you misread my post!
In article <cl**********@n ews5.svr.pol.co .uk>,
"luke" <lu*********@no emailspam.com> wrote: Wait, you mean, all that when this will do?
Wait, I think you misread my post!
Maybe. So now what?
--
Kris
<kr*******@xs4a ll.netherlands> (nl)
luke wrote: <td width="49%" background="lef t.gif"><img src="shim.gif" alt="" <td width="2%" valign="top"> ALL CONTENT </td> <td width="49%" background="rig ht.gif"><img src="shim.gif" alt="" This seems to work perfectly, however I'm slighlty unsure as the numbers don't add up.
My math says that 49 + 2 + 49 = 100. Seems to add up.
Say my Content in the middle cell is a 750 pixel wide nested table, this would obviously mean that the percentage are not as described.
Why do you care? You already ignore the percentages to get an
expandable middle section. If the total image widths exceed the viewable
area, the table expands beyond the view.
You'd have to view the result with different browsers to verify how
they handle it.
--
jmm dash list (at) sohnen-moe (dot) com
(Remove .AXSPAMGN for email)
luke wrote: I need to have two different backgrounds, one on the left and one on the right of the screen, with the main content centered in the browser. This is the code I have come up with
Join the two backgrounds together using a graphics program then use
Kris' example with this single background.
--
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