Help with Loop until "X" please

[sooli]

Hi, I feel foolish - I am trying to do a very simple thing... I have a loop to gather input from a user and I want it to allow seamless entry until the user enters an X then I want it to spit out a small method that tallys the info up.

so here's my snippit:

while(dat != "x" || dat != "X")
 
{
 cout << "" << endl;
 cin >> dat;
 num=stod(dat);
 stat1.next(num);
}
 
stat1.screenPrint();
 
 
 

it steps thru the loop just fine till I hit X then it craps out on me and I get a Debug Error.

Debug Error!
program:...al studio 2012\Projects\Statistician2\Debug\Statistician2.ex e
R6010
-abort() has been called
(Press Retry to debug the application)

If I hit ignore it just quits

it never exits the loop properly... what am I missing?

[mukherjee]

You may use Vector to store the inputs.

[weaknessforcats]

You are using an OR. So if you enter x, it's not an X and you stay in the loop. If you enter X, it's not an x and you stay in the loop.

Use the AND:

Try:

while(dat != "x" && dat != "X")
 
{
etc...

Now you stay in the loop if the dat is not x AND not X.

Also "x" and "X" are strings whereas 'x' and 'X' are chars. Ther may be an issue here but I don't the see definition of dat so I don't know.

[donbock]

stod on line 6 throws an invalid-argument exception when you enter "X" because that is not a valid number. Notice that "X" and "x" are not the only possible invalid arguments to stod.

What does it mean to "hit ignore"?