printing of array of strings is printing null instead of printing the result

[abhay123]

i m trying to print the array of string using this code but the compiler is printing null in the output:the code is as follows:

char *arr[10];
int i;
for(i=0;i<10;i++)
scanf("%s",*(arr+i));
 
for(i=0;i<10;i++)
printf("%s\n",*(arr+i));

[stdq]

Hello! When you're reading each character to the array, use %c instead of %s. Also, when you're printing each character, use %c, or, more simply, just use

printf("%s", arr)

instead of trying to print each character separately. If you prefer to do it that way, use %c instead of %s, and print only until you find the terminating '\0' character.

There is one more thing: you should either declare the array with 11 positions or only read until i is 8, because there must be space for the '\0' character, which, in this program, I'm not sure would be inserted automatically.

[weaknessforcats]

@stdq
This is about an array of strings and not a single string.

@abhay123
Your array is an array of 10 pointers to char. I'm guessing you want each pointer to point to a string. However, you have not allocated memory for any strings.

You cannot scanf into arr using %s because %s is for a string. A string is an array of char whereas your array is an array of char pointers.

[stdq]

@weaknessforcats: sorry about that! ^^