how to make a recursion count up and stop at its input

[george8000]

at the moment my code counts backwards by i need it to count forward while keeping the recursion. I cant get rid of it.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>

void printcount(int);

int main(int argc, char *argv[]){

int sum =0;

if(argc == 2){ //checks if the arguments entered is exactly two
if(isdigit(*argv[1]) ==0){ // checks if second argument is a number
fprintf(stderr,"Usage: ./count+ number \n"); //if not usage error
return EXIT_FAILURE; // and end program $
} else if(isdigit(*argv[1]) !=0){ // if it is then stores the number
sscanf(argv[1],"%d",&sum);; //in sum
printcount(sum);
printf("%d\n",sum);
}
} else{
fprintf(stderr,"Usage: ./count+ number \n");// if argument not exactly
return EXIT_FAILURE; //two then usage error and end of program
}
return EXIT_SUCCESS;
}

void printcount(int n){

if(n>0){
printf("%d,");
printcount(n-1);
}
return;
}

[weaknessforcats]

Change your printcount function to not have av hard-coded subtract. Instead, add another argument which tells printcount whether to add or subtract.

Maybe this argument if positive is the limt of the recursion for add and if negative means to sutract.

Or maybe add two arguments. One says whether to add or subtract and the other says by how much.