URGENT - how to make 0 to stop?

[lavender]

I have one C programming problem:

Enter value, 0 to stop:
15
26
45
0
List now : 15 26 45 0 37814140
Value to change : 26
Want to change with value: 45
List now: 15 45 26 0 37814140

The problem is when I key in 0, it should stop, and the list only can show up to 45 only.
Why my output show 0 and 37814140, izzit my code is worng?

Below is my code:

#include <stdio.h>
#define max 5
int main()
{
    int num[max], i=0;
    int swapFromNum = 0;
    int swapToNum = 0;
    int swapFromArrIndex = 0;
    int swapToArrIndex = 0;
    bool swapFromNumFound = false, swapToNumFound = false;
 
    printf("Enter value , 0 to stop: \n");
    while(1)
      {
       scanf("%d", &num[i]);   // read value
       if(num[i]==0)
       break;       // if 0 finished
       i++;
      }
 
    printf("List now: ");
 
      for(i=0;i<max;i++)
       {
        printf("%d ",num[i]);
       }
       printf("\n");
 
 
     printf("Value to change:");
     scanf("%d",&swapFromNum);

and some more....

[Ganon11]

Suppose the user enters 3 values, then 0. (35, 20, 14, 0). Then there are only 4 values in the array - the 5th element is garbage, correct?

But when you display the list, you loop i from 0 to max (which is 5), printing every element of the array, garbage or not. You should keep track of how many values the user entered before the 0.

[AdrianH]

Suppose the user enters 3 values, then 0. (35, 20, 14, 0). Then there are only 4 values in the array - the 5th element is garbage, correct?

But when you display the list, you loop i from 0 to max (which is 5), printing every element of the array, garbage or not. You should keep track of how many values the user entered before the 0.

And you might notice that if you enter 10 numbers, strange things may happen after 5 and you may crash your programme.


Adrian