what is the meaning of the **argv and **++argv in the code below?

[khagesh gupta]

 
 
/* myprog.c */
#include<stdio.h>
 
int main(int argc, char **argv)
{
    printf("%c\n", **++argv);
    return 0;
}
 
 

this question i found on http://www.indiabix.com/c-programming/command-line-arguments/068001
with ans o but without explaination.
help me out

[weaknessforcats]

So, if argv is an array of atrings, then *argv is a string in the array, then **argv is a character in that string.

[donbock]

You can't understand the result without knowing how the program was invoked. From the link you provided, it was:

cmd> myprog one two three 

The behavior of main arguments argc and argv are defined by the C Standard. Are you familiar with them?
Can you predict what their values are upon entry to main?