Hello,
I'm trying to print out a const char* buffer
by first printing 16 bytes as hex codes,
then printing them again as characters
or dots (if they aren't printable) and so on:
20 A5 96 74 00 00 00 00 05 AD 4A 7C D3 FF 70 00 ..t......J|..p.
31 B0 66 7F 9F 3D AC 00 9D FF C2 02 AB 10 28 76 1.f..=........(v
49 9A 5E 7C F7 3D E4 00 35 F9 3A 02 83 00 E0 76 I.^|.=..5.:....v
Right now it's too late here in Germany
and I have come up with this fugliness only:
void
dump_buffer(unsigned n, const unsigned char* buf)
{
const unsigned char *p, *end;
unsigned i, j;
end = buf + n;
for (i = 0; ; i += 16) {
p = buf + i;
for (j = 0; j < 16; j++) {
fprintf(stderr, "%02X ", p[j]);
if (p + j >= end)
goto BREAKOUT;
}
fprintf(stderr, " ");
p = buf + i;
for (j = 0; j < 16; j++) {
fprintf(stderr, "%c", isprint(p[j]) ? p[j] :
'.');
if (p + j >= end)
goto BREAKOUT;
}
fprintf(stderr, "\n");
}
BREAKOUT:
return;
}
I know that it's horrible. Maybe I'll do better tomorrow.
Does maybe any kind soul has a nice solution
for this probably often encountered problem?
I've looked at the Vim's xxd source code, but
it is too much for me to understand right now...
Thank you
Alex 5 27829
"A. Farber" <Al**************@gmail.comwrote in message
news:b1**********************************@v17g2000 hsa.googlegroups.com...
Hello,
I'm trying to print out a const char* buffer
by first printing 16 bytes as hex codes,
then printing them again as characters
or dots (if they aren't printable) and so on:
20 A5 96 74 00 00 00 00 05 AD 4A 7C D3 FF 70 00 ..t......J|..p.
31 B0 66 7F 9F 3D AC 00 9D FF C2 02 AB 10 28 76 1.f..=........(v
49 9A 5E 7C F7 3D E4 00 35 F9 3A 02 83 00 E0 76 I.^|.=..5.:....v
Right now it's too late here in Germany
and I have come up with this fugliness only:
void
dump_buffer(unsigned n, const unsigned char* buf)
{
const unsigned char *p, *end;
unsigned i, j;
end = buf + n;
for (i = 0; ; i += 16) {
p = buf + i;
for (j = 0; j < 16; j++) {
fprintf(stderr, "%02X ", p[j]);
if (p + j >= end)
goto BREAKOUT;
}
fprintf(stderr, " ");
p = buf + i;
for (j = 0; j < 16; j++) {
fprintf(stderr, "%c", isprint(p[j]) ? p[j] :
'.');
if (p + j >= end)
goto BREAKOUT;
}
fprintf(stderr, "\n");
}
BREAKOUT:
return;
}
I know that it's horrible. Maybe I'll do better tomorrow.
Does maybe any kind soul has a nice solution
for this probably often encountered problem?
I've looked at the Vim's xxd source code, but
it is too much for me to understand right now...
Thank you
Alex
Untested but
void dumpbuff(char *buff, int N)
{
int i;
for(i=0;i<N;i+=16
if(i + 16 <= N)
printline(data+i, 16);
else
printline(data+1, N - i);
}
void printline(char *data, int N)
{
int i;
for(i=0;i<N;i++)
printf("%02x ", data[i]):
printf(" ");
for(i=0;i<N;i++)
if(isgraph((unsigned) data[i]))
printf("%c", data[i]);
else
printf(".");
printf("\n");
}
As long as you break things up the right way the function can look nice and
clean.
--
Free games and programming goodies. http://www.personal.leeds.ac.uk/~bgy1mm
"A. Farber" <Al**************@gmail.comwrites:
I'm trying to print out a const char* buffer
by first printing 16 bytes as hex codes,
then printing them again as characters
or dots (if they aren't printable) and so on:
20 A5 96 74 00 00 00 00 05 AD 4A 7C D3 FF 70 00 ..t......J|..p.
31 B0 66 7F 9F 3D AC 00 9D FF C2 02 AB 10 28 76 1.f..=........(v
49 9A 5E 7C F7 3D E4 00 35 F9 3A 02 83 00 E0 76 I.^|.=..5.:....v
<snip>
Does maybe any kind soul has a nice solution
for this probably often encountered problem?
I'd do this:
void dump_buffer(unsigned n, const unsigned char* buf)
{
int on_this_line = 0;
while (n-- 0) {
fprintf(stderr, "%02X ", *buf++);
on_this_line += 1;
if (on_this_line == 16 || n == 0) {
int i;
fputs(" ", stderr);
for (i = on_this_line; i < 16; i++)
fputs(" ", stderr);
for (i = on_this_line; i 0; i--)
fputc(isprint(buf[-i]) ? buf[-i] : '.', stderr);
fputs("\n", stderr);
on_this_line = 0;
}
}
}
--
Ben.
Peter Nilsson <ai***@acay.com.auwrites:
"A. Farber" <Alexander.Far...@gmail.comwrote:
<snip>
>fprintf(stderr, "%c", isprint(p[j]) ? p[j] : '.');
Note that isprint() for \n, \t, \b, \r, etc... are likely
to be true.
That is at odds with my reading of the standard (specifically
paragraph 3 of 7.4). Am I misunderstanding what you mean?
--
Ben.
Ben Bacarisse <ben.use...@bsb.me.ukwrote:
Peter Nilsson <ai...@acay.com.auwrites:
"A. Farber" <Alexander.Far...@gmail.comwrote:
fprintf(stderr, "%c", isprint(p[j]) ? p[j] : '.');
Note that isprint() for \n, \t, \b, \r, etc... are likely
to be true.
That is at odds with my reading of the standard (specifically
paragraph 3 of 7.4). *Am I misunderstanding what you mean?
No, I was wrong. Thanks for the correction.
--
Peter This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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