function declaration

[magnacarta]

#include<iostream.h> #include<iostream.h>
#include<conio.h>
#include<math.h>

void display()
int main()
{
int a=9;
int b=10;
clrscr();
cout<<display(a,b)<<"\n";
return 0;
getch();
}
void display(int A[] [],int m, int n)
{
int i,j;
for (i=0;i<m;i++)
for (j=0;j<n;j++)
cout<<" "<<A[i][j];
cout<<"\n";
}

i have listed my program to call a function above but it is showing an error as below in line 5 called ' Declaration syntax error'

kindly help me solve this

[Meetee]

#include<iostream.h> #include<iostream.h>
#include<conio.h>
#include<math.h>

void display()
int main()
{
int a=9;
int b=10;
clrscr();
cout<<display(a,b)<<"\n";
return 0;
getch();
}
void display(int A[] [],int m, int n)
{
int i,j;
for (i=0;i<m;i++)
for (j=0;j<n;j++)
cout<<" "<<A[i][j];
cout<<"\n";
}

i have listed my program to call a function above but it is showing an error as below in line 5 called ' Declaration syntax error'

kindly help me solve this

You have define and declare same function with different parameters!!! I am pointing to void display()

Regards

[joeschnell]

Yeah, I'm just starting CIS247 and went through functions briefly but, he is right on the paramaters. When you declare your function within the () you need to list the same paramaters as you use below in your code using the & before repeated use declarations.

functions (one, &two, three, four, &five, six)

int main ()

...
...
...
..now you call it
functions (here you need to call out the parameters the same as above)
(one, two, three, four, five, six)
Your code seems pretty sophisticated to not know how to call a function. Hope you get it. Joe

[joeschnell]

void display (int, &double, &double, &char, int, double)


when calling

void display (int, double, double, char, int, double)

or close to that--later

[magnacarta]

void display (int, &double, &double, &char, int, double)


when calling

void display (int, double, double, char, int, double)

or close to that--later

hi Joe, thanx for the help i made the changes but it shows 2 errors now.
1. size of the type is unknown or zero and 2. declaration is expected

i m pasting the program again with my changes

#include<iostream.h> #include<iostream.h>
#include<conio.h>
#include<math.h>
void display(int A[] [],int m, int n,)
int main()
{
int a=9;
int b=10;
clrscr();
cout<<display(a,b)<<"\n";
return 0;
getch();
}
void display(int A[] [],int m, int n)
{
int i,j;
for (i=0;i<m;i++)
for (j=0;j<n;j++)
cout<<" "<<A[i][j];
cout<<"\n";
}

kindly b patient as i have just started learning C++ and am doing it on my own with aid from you guys and this site

[Meetee]

hi Joe, thanx for the help i made the changes but it shows 2 errors now.
1. size of the type is unknown or zero and 2. declaration is expected

i m pasting the program again with my changes

#include<iostream.h> #include<iostream.h>
#include<conio.h>
#include<math.h>
void display(int A[] [],int m, int n,)
int main()
{
int a=9;
int b=10;
clrscr();
cout<<display(a,b)<<"\n";
return 0;
getch();
}
void display(int A[] [],int m, int n)
{
int i,j;
for (i=0;i<m;i++)
for (j=0;j<n;j++)
cout<<" "<<A[i][j];
cout<<"\n";
}

kindly b patient as i have just started learning C++ and am doing it on my own with aid from you guys and this site

Hi magnacarta,

Again you check your code. You are calling display with two parameters and function is defined/declared with 3 parameters. You can define array locally in display function as you are just printing the value locally.

Regards

PS. Kindly put code tags around code

[archonmagnus]

Just for comparison:

#include<iostream>  // removed trailing ".h"
#include<conio.h>   // careful, this is a Windows only library!!!
#include<cmath>     // changed from "math.h" to "cmath"
 
// old declaration: notice there is a comma after 'n'
//    and no semicolon at the end of the prototype
// void display(int A[] [],int m, int n,)
 
// new function prototype
void display (int a, int b);
 
int main()
{
    int a=9;
    int b=10;
 
    // ...stuff before function call...
    cout<<display(a,b)<<"\n";
    // ... stuff after function call...
}
 
// old declaration
//void display(int A[] [],int m, int n)
void display (int a, int b)
{
    // ...stuff in function...
}
 

Or if you still need the array, then the function call is the part of the code that needs to be edited. i.e., you'd need to add the array to be passed to the function.

[anubhavit]

#include<iostream.h> #include<iostream.h>
#include<conio.h>
#include<math.h>

void display()
int main()
{
int a=9;
int b=10;
clrscr();
cout<<display(a,b)<<"\n";
return 0;
getch();
}
void display(int A[] [],int m, int n)
{
int i,j;
for (i=0;i<m;i++)
for (j=0;j<n;j++)
cout<<" "<<A[i][j];
cout<<"\n";
}

i have listed my program to call a function above but it is showing an error as below in line 5 called ' Declaration syntax error'

kindly help me solve this

The error in the program is that you are not passing the 3 arguments that you are making use of in the function. Change the display function to
void display(int m, int n)
{int A[3] [3];
int i,j;
for (i=0;i<m;i++)
for (j=0;j<n;j++)
printf("%d",A[i][j]);
printf("\n");
}
and your program should work

[magnacarta]

The error in the program is that you are not passing the 3 arguments that you are making use of in the function. Change the display function to
void display(int m, int n)
{int A[3] [3];
int i,j;
for (i=0;i<m;i++)
for (j=0;j<n;j++)
printf("%d",A[i][j]);
printf("\n");
}
and your program should work

i made the changes as to my understanding but not there is an error 'Declaration syntax error' in line 5. could some one kindly make this program error free put it here. sorry but thanx

[weaknessforcats]

void display(int m, int n)
{int A[3] [3];
int i,j;
for (i=0;i<m;i++)
for (j=0;j<n;j++)
printf("%d",A[i][j]);
printf("\n");
}

You have nested for loops but no braces:

for (etc...)
{
      for (etc...)
      {
 
      }
}
 

Also, the array is a local variable so there is no way to get values in the array from main(). Did you mean to do that??? Or did you mean to create the array in main() and then call the function to display the array?? I thinkl you still have a logic problem.

[phiefer3]

hi Joe, thanx for the help i made the changes but it shows 2 errors now.
1. size of the type is unknown or zero and 2. declaration is expected

i m pasting the program again with my changes

#include<iostream.h> #include<iostream.h>
#include<conio.h>
#include<math.h>
void display(int A[] [],int m, int n,)
int main()
{
int a=9;
int b=10;
clrscr();
cout<<display(a,b)<<"\n";
return 0;
getch();
}
void display(int A[] [],int m, int n)
{
int i,j;
for (i=0;i<m;i++)
for (j=0;j<n;j++)
cout<<" "<<A[i][j];
cout<<"\n";
}

kindly b patient as i have just started learning C++ and am doing it on my own with aid from you guys and this site

Magnacarta, so far in every one of your posts, you also forgot the ; at the end of your prototype in line 5:

void display(int A[] [],int m, int n,)

should be

void display(int A[] [],int m, int n,);