Calling Hidden Function

[WarcraftNoob]

Say i have 3 functions

void foo(int x);
void print(void);
int main(void);


main calls print, and print printfs out some information getting user input before exiting back to main.

However foo is not called in main, but needs to be called outside the program without it being modified, how can I go about doing this

foo does a printf when x = 3 and exits(0);

I was reading online and found something about using #pragma but I dont know it I can go forth with it.

Only languages I know are C, assembly and a little Java. Can you please give me suggestions on how to go about this problem.

I will PM you the source it you need more clarification. Thanks in advance. :)

[DeMan]

I'm not too surwe how #pragma works, there is plenty of resource for it on the net, but it don't make much sense to me......

If you want to make a metho globally visible, however, you can declare its' prototype/signature (that is the top line of the method followed by a semicolon) in a header file (.h) file.

[WarcraftNoob]

Ok I made some progress and I found that I have to do something along the lines of this

http://community.corest.com/~juliano...t_tutorial.txt

Example above, has

void lame (void) { char small[30]; gets (small); printf("%s\n", small); }
main() { lame (); return 0; }


but mine is
void foo(int x){ if (x==0x2345} printf("what"); exit(0);}
void lame (void) { char small[30]; gets (small); printf("%s\n", small); }
main() { lame (); return 0; }

I need to get to execute the foo function, I followed the above tutorial but im stuck at Step 3b. Somebody please clarify this with me thanks

[DeMan]

main() { 
   lame ();
   foo(0x2345);  //or any other value if you don't want to see the what
  return 0;
}
 

[WarcraftNoob]

main() { 
   lame ();
   foo(0x2345);  //or any other value if you don't want to see the what
  return 0;
}
 

i cannot touch the original source, i have to do it from outside the program