how to make this possible

[nik]

hello friends, the following code is not running but it replace n by j
& create error i.e. undeclared tokenj . but i want to call
token0,token1 from the loop in main.how it could be achieved.plz tell
me

#include <iostream.h>
#define paster(n) token##n##() //token pasting
int token1() //token1() defination
{
return 1;

}
int token0() //token1() defination
{
return 0;

}
void main( )
{
for(int j=0;j<2;j++) //for Loop for j=0,1
{
int i=paster(j); //to call
token0(),token1()
cout<<"\n"<<i;
}
}

[Rolf Magnus]

nik wrote:

hello friends, the following code is not running but it replace n by j
& create error i.e. undeclared tokenj . but i want to call
token0,token1 from the loop in main.how it could be achieved.plz tell
me

This is not possible. The names are static at compile time and typicall
don't exist anymore at runtime. You want them to be dynamically chosen. The
paster() macro is resolved in the preprocessor, before the actual compiler
even sees the code.
Use a vector of function pointers instead.

#include <iostream.h>

Non-standard header.

#define paster(n) token##n##() //token pasting
int token1() //token1() defination
{
return 1;

}
int token0() //token1() defination
{
return 0;

}
void main( )

main() must return int.

{
for(int j=0;j<2;j++) //for Loop for j=0,1
{
int i=paster(j); //to call
token0(),token1()
cout<<"\n"<<i;
}
}

[nik]

plz tell me the coding for that
Rolf Magnus wrote:

nik wrote:

hello friends, the following code is not running but it replace n by j
& create error i.e. undeclared tokenj . but i want to call
token0,token1 from the loop in main.how it could be achieved.plz tell
me

This is not possible. The names are static at compile time and typicall
don't exist anymore at runtime. You want them to be dynamically chosen. The
paster() macro is resolved in the preprocessor, before the actual compiler
even sees the code.
Use a vector of function pointers instead.

#include <iostream.h>

Non-standard header.

#define paster(n) token##n##() //token pasting
int token1() //token1() defination
{
return 1;

}
int token0() //token1() defination
{
return 0;

}
void main( )

main() must return int.

{
for(int j=0;j<2;j++) //for Loop for j=0,1
{
int i=paster(j); //to call
token0(),token1()
cout<<"\n"<<i;
}
}

[Thorsten Kiefer]

nik wrote:

plz tell me the coding for that
Rolf Magnus wrote:

#include <iostream.h>

Non-standard header.

#define paster(n) token##n##() //token pasting
int token1() //token1() defination
{
return 1;

}
int token0() //token1() defination
{
return 0;

}
void main( )

main() must return int.

{
for(int j=0;j<2;j++) //for Loop for j=0,1
{
int i=paster(j); //to call
token0(),token1()
cout<<"\n"<<i;
}
}

#include <iostream.h>
using namespace std;

int token1() //token1() defination
{
return 1;
}
int token0() //token1() defination
{
return 0;
}

typedef int MyFunction();
MyFunction myfunctions[] = {token0,token1};

int main(){
for(int i = 0;i < 2;++i)
cout << myfuntions[i]() << endl;
}

[Howard]

"Thorsten Kiefer" <th************@gmx.dewrote in message
news:eb**********@news01.versatel.de...

typedef int MyFunction();

That's not correct. You meant to define a function pointer, right I think
it's:

typedef int (*MyFunction)();

MyFunction myfunctions[] = {token0,token1};

int main(){
for(int i = 0;i < 2;++i)
cout << myfuntions[i]() << endl;

typo: myfunctions

}

-Howard