Question about arrays..

[kiddler]

I'm sorta new to the C++ syntax.

I know that arrays can be delcared like so:
int a[]={1,2,3,4};

but what if I want the array to be a global, and then set the length
and value inside a method?

like in java, you can do:

int a[];
void main()
{
a=new int{1,2,3,4};
}

How do I do that in C++?

[Jerry Coffin]

In article <11*********************@m73g2000cwd.googlegroups. com>,
ne*************@gmail.com says...

I'm sorta new to the C++ syntax.

I know that arrays can be delcared like so:
int a[]={1,2,3,4};

but what if I want the array to be a global, and then set the length
and value inside a method?

You can't do it (not directly anyway). If you want to do that, you're
probably better off using an std::vector instead.

--
Later,
Jerry.

The universe is a figment of its own imagination.

[kiddler]

I see... I'll look that up, thanks alot

[AB]

like in java, you can do:

>
int a[];
void main()
{
a=new int{1,2,3,4};
}

How do I do that in C++?

No direct method, but you can try this..

int* a ;//global declaration

void method()
{
a = new int[size] ;
for(i = 0; i < size; i++)
a[i] = value ;
}

[chriskr7]

AB wrote:

like in java, you can do:

int a[];
void main()
{
a=new int{1,2,3,4};
}

How do I do that in C++?

No direct method, but you can try this..

int* a ;//global declaration

void method()
{
a = new int[size] ;
for(i = 0; i < size; i++)
a[i] = value ;
}

another way -

int* a;

void method()
{
int b[] = {1, 2, 3, 4};
a = new int [4];
memcpy(a, b, 4);
//think it's better for speed of performance
}//

[Thomas J. Gritzan]

AB schrieb:

>like in java, you can do:

int a[];
void main()

main returns an int:

int main()

>{
a=new int{1,2,3,4};
}

How do I do that in C++?

No direct method, but you can try this..

int* a ;//global declaration

void method()
{
a = new int[size] ;
for(i = 0; i < size; i++)
a[i] = value ;
}

Don't do it the Java way when you program C++. Where would you delete[]
the pointer?

Better would be a std::vector as Jerry suggests:

#include <vector>

std::vector<inta;

int main()
{
a.push_back(1);
a.push_back(2);
a.push_back(3);
a.push_back(4);

// or:
a.resize(4);
for (int i = 0; i < 4; i++)
a[i] = i+1;
}

--
Thomas

[Victor Bazarov]

Thomas J. Gritzan wrote:

AB schrieb:

>>like in java, you can do:

int a[];
void main()

main returns an int:

int main()

>>{
a=new int{1,2,3,4};
}

How do I do that in C++?

No direct method, but you can try this..

int* a ;//global declaration

void method()
{
a = new int[size] ;
for(i = 0; i < size; i++)
a[i] = value ;
}

Don't do it the Java way when you program C++. Where would you
delete[] the pointer?

Better would be a std::vector as Jerry suggests:

#include <vector>

std::vector<inta;

int main()
{
a.push_back(1);
a.push_back(2);
a.push_back(3);
a.push_back(4);

// or:
a.resize(4);
for (int i = 0; i < 4; i++)
a[i] = i+1;
}

Why is 'a' *global*? Is there really *the need* for it to be global?

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

[Thomas J. Gritzan]

Victor Bazarov schrieb:

Thomas J. Gritzan wrote:

>Don't do it the Java way when you program C++. Where would you
delete[] the pointer?

Better would be a std::vector as Jerry suggests:

#include <vector>

std::vector<inta;

int main()
{
a.push_back(1);
a.push_back(2);
a.push_back(3);
a.push_back(4);

// or:
a.resize(4);
for (int i = 0; i < 4; i++)
a[i] = i+1;
}

Why is 'a' *global*? Is there really *the need* for it to be global?

Because the OP wanted it:

but what if I want the array to be a global, and then set the length
and value inside a method?

I wonder how he got the global in Java to work...

--
Thomas

[Frederick Gotham]

kiddler posted:

I'm sorta new to the C++ syntax.

I know that arrays can be delcared like so:
int a[]={1,2,3,4};

but what if I want the array to be a global, and then set the length
and value inside a method?

like in java, you can do:

int a[];
void main()
{
a=new int{1,2,3,4};
}

How do I do that in C++?

std::vector would probably be the way to go.

Or if you're feeling creative. . .

template<class T>
class Array {
private:

T *pNC;
unsigned lenNC;

public:

T * const p;

unsigned const &len;
Array() : p(pNC), len(lenNC) {}

void Allocate(unsigned const quantity)
{
lenNC = quantity;

pNC = new T[len];
}

void Deallocate()
{
delete [] pNC;
}
};
Array<inta;
int main()
{
a.Allocate(4);

a.p[0] = 1; a.p[1] = 2; a.p[2] = 3; a.p[3] = 4;
...
a.Deallocate();
}

--

Frederick Gotham

[Victor Bazarov]

Frederick Gotham wrote:

kiddler posted:

>I'm sorta new to the C++ syntax.

I know that arrays can be delcared like so:
int a[]={1,2,3,4};

but what if I want the array to be a global, and then set the length
and value inside a method?

like in java, you can do:

int a[];
void main()
{
a=new int{1,2,3,4};
}

How do I do that in C++?

std::vector would probably be the way to go.

Or if you're feeling creative. . .

template<class T>
class Array {
private:

T *pNC;
unsigned lenNC;

public:

T * const p;

unsigned const &len;
Array() : p(pNC), len(lenNC) {}

Neither 'pNC' nor 'lenNC' are initialised. Initialising other members
with their values (indeterminate, BTW), is very dangerous.

>
void Allocate(unsigned const quantity)
{
lenNC = quantity;

pNC = new T[len];

This doesn't seem to do anything with 'p'. What is 'p' for, then?

}

void Deallocate()
{
delete [] pNC;
}
};
Array<inta;
int main()
{
a.Allocate(4);

a.p[0] = 1; a.p[1] = 2; a.p[2] = 3; a.p[3] = 4;

Undefined behaviour. You're dereferencing an uninitialised pointer.

>

...
a.Deallocate();
}

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

[Thomas J. Gritzan]

Victor Bazarov schrieb:

Frederick Gotham wrote:

>Or if you're feeling creative. . .

template<class T>
class Array {
private:

T *pNC;
unsigned lenNC;

public:

T * const p;

unsigned const &len;
Array() : p(pNC), len(lenNC) {}

Neither 'pNC' nor 'lenNC' are initialised. Initialising other members
with their values (indeterminate, BTW), is very dangerous.

> void Allocate(unsigned const quantity)
{
lenNC = quantity;

pNC = new T[len];

This doesn't seem to do anything with 'p'. What is 'p' for, then?

Maybe p is supposed to be a reference like len.
Doesn't change the fact that it's bad advice, and that there is no
destructor.

> }

void Deallocate()
{
delete [] pNC;
}
};

--
Thomas

[Frederick Gotham]

Thomas J. Gritzan posted:

Maybe p is supposed to be a reference like len.
Doesn't change the fact that it's bad advice, and that there is no
destructor.

Yes, the code was unchecked, and I posted in haste.

"p" was supposed to be a reference.

--

Frederick Gotham