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# Trying to pass values of variables from a redefined function into another function

 P: n/a Here's the problem: I have a function that references another one in this manner: class circleType: public pointType so, pointType is redefined by circleType, thereby giving circleType access to all the functions in pointType if need-be. Here is the function I am using in pointType: void pointType::setCoords(double xCoord, double yCoord) { pointX = xCoord; pointY = yCoord; } it is being accessed in circleType in this manner: void circleType::getCoords(double xCoord, double yCoord) { //set the external point using the pointType header pointType::setCoords(pointX, pointY); cout << "The coordinate entered is: (" << pointX << "," << pointY << ")"; cout << endl; } My cout works, but the point it prints is (0,0), meaning that the variables aren't being passed into the function, and it is just defaulting to the value of 0 for both. Any thoughts? Oct 23 '05 #1
4 Replies

 P: n/a deanfamily wrote: Here's the problem: I have a function that references another one in this manner: class circleType: public pointType so, pointType is redefined by circleType, thereby giving circleType access to all the functions in pointType if need-be. Here is the function I am using in pointType: void pointType::setCoords(double xCoord, double yCoord) { pointX = xCoord; pointY = yCoord; } it is being accessed in circleType in this manner: void circleType::getCoords(double xCoord, double yCoord) { //set the external point using the pointType header pointType::setCoords(pointX, pointY); cout << "The coordinate entered is: (" << pointX << "," << pointY << ")"; cout << endl; } My cout works, but the point it prints is (0,0), meaning that the variables aren't being passed into the function, and it is just defaulting to the value of 0 for both. Any thoughts? Code isn't very descriptive but seem as though you're passing uninitialized member variables of the pointType to PointType: void circleType::getCoords(double xCoord, double yCoord) { //set the external point using the pointType header pointType::setCoords(pointX, pointY); .... did you mean: pointType::setCoords(xCoord, yCoord) ? Oct 23 '05 #2

 P: n/a Even with it corrected to void circleType::getCoords(double xCoord, double yCoord) { //set the external point using the pointType header pointType::setCoords(xCoord, yCoord); cout << "The coordinate entered is: (" << pointX << "," << pointY << ")"; cout << endl; } it still isn't passing the amounts. "puzzlecracker" wrote in message news:11*********************@f14g2000cwb.googlegro ups.com... deanfamily wrote: Here's the problem: I have a function that references another one in this manner: class circleType: public pointType so, pointType is redefined by circleType, thereby giving circleType access to all the functions in pointType if need-be. Here is the function I am using in pointType: void pointType::setCoords(double xCoord, double yCoord) { pointX = xCoord; pointY = yCoord; } it is being accessed in circleType in this manner: void circleType::getCoords(double xCoord, double yCoord) { //set the external point using the pointType header pointType::setCoords(pointX, pointY); cout << "The coordinate entered is: (" << pointX << "," << pointY << ")"; cout << endl; } My cout works, but the point it prints is (0,0), meaning that the variables aren't being passed into the function, and it is just defaulting to the value of 0 for both. Any thoughts? Code isn't very descriptive but seem as though you're passing uninitialized member variables of the pointType to PointType: void circleType::getCoords(double xCoord, double yCoord) { //set the external point using the pointType header pointType::setCoords(pointX, pointY); .... did you mean: pointType::setCoords(xCoord, yCoord) ? Oct 23 '05 #3

 P: n/a deanfamily wrote: Here's the problem: I have a function that references another one in this manner: class circleType: public pointType This means nothing. Be careful to use the correct terms for the concepts. What's more, some code is worth a thousand words, so they say. so, pointType is redefined by circleType, thereby giving circleType access to all the functions in pointType if need-be. Here is the function I am using in pointType: void pointType::setCoords(double xCoord, double yCoord) { pointX = xCoord; pointY = yCoord; } it is being accessed in circleType in this manner: void circleType::getCoords(double xCoord, double yCoord) get or set? { //set the external point using the pointType header pointType::setCoords(pointX, pointY); cout << "The coordinate entered is: (" << pointX << "," << pointY << ")"; cout << endl; } My cout works, but the point it prints is (0,0), meaning that the variables aren't being passed into the function, and it is just defaulting to the value of 0 for both. Something on line 42, perhaps? Seriously, the code you gave is obviously correct, so some wild guesses: 1) circleType also has members named pointX and pointY which takes precedence over pointType's in the std::cout 2) you passed 0,0 when you called getCoords (or setCoords?) 3) another thread modify the variables 4) main returns void 5) you have a virus What does the debugger says? Is there more code to this program? Something we could test ourselves? Jonathan Oct 23 '05 #4

 P: n/a deanfamily wrote: Even with it corrected to void circleType::getCoords(double xCoord, double yCoord) { //set the external point using the pointType header pointType::setCoords(xCoord, yCoord); cout << "The coordinate entered is: (" << pointX << "," << pointY << ")"; cout << endl; } it still isn't passing the amounts. "puzzlecracker" wrote in message news:11*********************@f14g2000cwb.googlegro ups.com... deanfamily wrote: Here's the problem: I have a function that references another one in this manner: class circleType: public pointType so, pointType is redefined by circleType, thereby giving circleType access to all the functions in pointType if need-be. Here is the function I am using in pointType: void pointType::setCoords(double xCoord, double yCoord) { pointX = xCoord; pointY = yCoord; } it is being accessed in circleType in this manner: void circleType::getCoords(double xCoord, double yCoord) { //set the external point using the pointType header pointType::setCoords(pointX, pointY); cout << "The coordinate entered is: (" << pointX << "," << pointY << ")"; cout << endl; } My cout works, but the point it prints is (0,0), meaning that the variables aren't being passed into the function, and it is just defaulting to the value of 0 for both. Any thoughts? Code isn't very descriptive but seem as though you're passing uninitialized member variables of the pointType to PointType: void circleType::getCoords(double xCoord, double yCoord) { //set the external point using the pointType header pointType::setCoords(pointX, pointY); .... did you mean: pointType::setCoords(xCoord, yCoord) ? I second it. Perhaps, computer science is not really for you. Can you still change the major? Oct 23 '05 #5

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