enum scope

[vsgdp]

Hi,

Do enumerators have scope?

class A
{
};
enum E {A, B, C};
int main()
{
E e = E::A;
}

Can ::A be distinguished from E::A?

[John Carson]

"vsgdp" <sp**@void.com> wrote in message
news:zi04f.2519$i%.522@fed1read07

Hi,

Do enumerators have scope?

class A
{
};
enum E {A, B, C};
int main()
{
E e = E::A;
}

Can ::A be distinguished from E::A?

There is no such thing as E::A. Enum values do have scope, but what that
means is the following:

enum Outer {A=0};

int main()
{
enum Inner {A=1};
int x = A; // x is 1, not 0
}
--
John Carson

[Ron Natalie]

vsgdp wrote:

Hi,

Do enumerators have scope?

class A
{
};
enum E {A, B, C};
int main()
{
E e = E::A;
}

Can ::A be distinguished from E::A?

The enumerators have the scope of where the enum is declared. In
this case at namespace scope. The class A and the enumerator A
are in the same namespace scope.

You could wrap a namespace around your enumerator if you wanted
differentiate:
class A ;
namespace E {
enum T { A, B, C };
};

E::T e = E::A;