how to return a value true if a given char is a vowel and false if not?

[phelle25]

i made a program in else-if statement about this problem.
but my teacher requires to give a return statement about this. i am new with in programming and we had just tackle a return statement and i find it hard to understand. please can u help me. or just give me an idea how to do it.
#include <stdio.h>
#include <conio.h>
int main ()
{
char a,e,i,o,u;
char letter,ans;
printf("\n\nent er another letter(1=yes,0= no)?");
scanf("%d",&ans );
if (ans==1){
printf("\nEnter a letter:");
scanf("%d",&let ter);
if (letter == 'a'){
printf("true"); }
else if (letter == 'e'){
printf("true"); }
else if (letter == 'i'){

printf("true");
}
else if (letter == 'o'){

printf("true");
}

else if (letter == 'u'){

printf("true");

}
else
{
printf("false") ;
}
while (ans==1)

getche ();
return 0;}
}
this is my program in if-else staement.

[whodgson]

@ JosAH
I don`t think that your link explains your solution very well... at least my first shot at applying it to what you wrote left me baffled (failed). Could you amplify a bit. I will dig further.
EDIT:
Tchtch Jos.... first your code would not compile because of null in lower case and then it declared AEIOU were not vowels!

#include<iostream>
using namespace std;
int isVowel(char c); 
 
int main()
{
char c;    
cout<<"Enter a character, call isVowel() and find if \n"
<<" TRUE or FALSE\n";
cout<<"Enter a character ";
cin>>c;
if(isVowel(c)==1)
cout<<"The character you entered is a vowel \n";
else cout<<"The character you entered is not a vowel \n";
cout<<endl<<endl;
system("pause");
return 0;
}
 
int isVowel(char c) 
{ 
   return strchr("aeiou", c) != NULL;// was null; 
} 

[phelle25]

hi,
thank u very much for the time and suggestions. actually i got the answer now and i passed th assignment. here it is:

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>

bool isvowel(char var);

main(){
char v;
bool r;
printf("\n\n\tE nter a Letter: ");
scanf("%c",&v);
r = isvowel(v);

if(r == true) {printf("\nLett er %c is a vowel", v);}
else printf("\nLette r %c is not a vowel",v);

getche();


}

bool isvowel(char var){
bool e;

if(var=='a'||va r=='A'||var=='e '||var=='E'||va r=='i'||var=='I '||var=='o'||va r == 'O'||var=='u'|| var=='U')
{
e = true;
}
else e = false;

return e;


}

God bless

[donbock]

Good for you!

I hope you'll be patient with me for a few pedantic observations.

1. Which of your headers defined the bool type?
2. If you're not using C99 and <stdbool.h>, then it is advisable to avoid comparing a bool variable directly to true -- as in if(r == true). There is only one false value (0), but all nonzero values are true. Your variable might have a different nonzero value than "true". I would replace this line with either if(r) or if(r != false).
3. Did you know you could replace the bulk of isvowel by return ((var=='a')||.. .||(var=='U'));? This construction is equivalent to your code.
4. The C Standard mandates that main return an int. In fact, your main function has an implicit int return value. Explicit is usually better than implicit. Either way, you need a return statement at the end of main.
5. Regarding the problem specification, should "Y" be considered a vowel? The vowel list I learned so many years ago was "A, E, I, O, U, and sometimes Y". If you're feeling whimsical, you could randomly choose between vowel or nonvowel if (and only if) the input character is "Y".

You have a working program, so don't change it. These observations are to help with your next project.

Cheers,
don