No format string passed to variable argument list function

[Adam]

Hi,

I have a simple printf-like function:

int print(const char *format, ...)
{
char buffer[1024];
va_list argptr;
int i;

va_start(argptr , format);
i = vsnprintf(buffe r, sizeof(buffer), format, argptr);
va_end(argptr);

buffer[sizeof(buffer)-1] = '\0';

printf("%s\n",b uffer); /* this bit just for the sake of testing */

return i;
}

If I call the function using something like:
char message[50];
strcpy(message, "hi there");
print("%s",mess age);

everything works, but if I do:
print(message);

it doesn't (program crashes with an abort).

Is there something wrong with what I'm doing, or should I be looking
elsewhere to work out the cause of my crash?

Thanks a lot,
Adam

[Harald van =?UTF-8?b?RMSzaw==?=]

On Tue, 11 Nov 2008 09:24:14 -0800, Tim Rentsch wrote:

Harald van =?UTF-8?b?RMSzaw==?= <tr*****@gmail. comwrites:

>On Sun, 09 Nov 2008 23:21:56 -0800, Tim Rentsch wrote:

Harald van =?UTF-8?b?RMSzaw==?= <tr*****@gmail. comwrites:
I think whatever location is used to store the return address
qualifies as an object, [...]

A return address is not a C value; hence storage for it is not an
object.

The storage for the return address is usually an object:
[...]

Despite 3.14 being worded the way it is, it seems clear that the term
"object" as it is used in the standard should be read as not including
return-address memory. Considering the requirements of 6.2.4, [...]

That's a good point. Considering those requirements, I can only agree that
the definition of object (or at least my interpretation of it) is too
broad, and whatever location holds a return address isn't or needn't be an
object.