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How to initialized a member array?

Hi,

I'm wondering if there is a way to initialized a member array just as
the initialization of a member variable? Or I have to initialized the
array inside the function body of the constructor?

Thanks,
Peng

#include <iostream>

struct A {
A() : array({0, 1, 2, 3}), variable(100) { }
int array[4];
int variable;
};
int main() {
A a;
std::cout << a.array[0] << std::endl;
std::cout << a.variable << std::endl;
}
Sep 4 '08 #1
2 2546
On Sep 3, 9:25*pm, Peng Yu <PengYu...@gmai l.comwrote:
Hi,

I'm wondering if there is a way to initialized a member array just as
the initialization of a member variable? Or I have to initialized the
array inside the function body of the constructor?

Thanks,
Peng

#include <iostream>

struct A {
* A() : array({0, 1, 2, 3}), variable(100) { }
* int array[4];
* int variable;

};

int main() {
* A a;
* std::cout << a.array[0] << std::endl;
* std::cout << a.variable << std::endl;

}
C++ does not support member array initialization via the initializer
list.

--
http://www.EventHelix.com/EventStudio
Sequence diagram based systems engineering tool
Sep 4 '08 #2
On Sep 4, 9:25*am, Peng Yu <PengYu...@gmai l.comwrote:
Hi,

I'm wondering if there is a way to initialized a member array just as
the initialization of a member variable? Or I have to initialized the
array inside the function body of the constructor?

Thanks,
Peng

#include <iostream>

struct A {
* A() : array({0, 1, 2, 3}), variable(100) { }
* int array[4];
* int variable;

};

int main() {
* A a;
* std::cout << a.array[0] << std::endl;
* std::cout << a.variable << std::endl;

}

Waiting for c++0x
Sep 4 '08 #3

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