Hello All,
I confronted recently with the fact that the size of a struct member
can't be determined with sizeof(Struct:: Member). I'm aware of the
alternative methods to do this, however, I'm interested in the
rationale why the Struct::Member syntax is disallowed.
Thanks, P
5  1770 
petschy wrote:
Hello All,
I confronted recently with the fact that the size of a struct member
can't be determined with sizeof(Struct:: Member). I'm aware of the
alternative methods to do this, however, I'm interested in the
rationale why the Struct::Member syntax is disallowed.
Was it even proposed?
If so, what benefits would it bring?
--
Ian Collins.
Was it even proposed?
I don't know.
If so, what benefits would it bring?
I needed the size of a member, without an actual instance and the
syntax 'felt' natural. This could be done, so I just wondered why is
it disallowed.
P
petschy wrote:
I confronted recently with the fact that the size of a struct member
can't be determined with sizeof(Struct:: Member). I'm aware of the
alternative methods to do this, however, I'm interested in the
rationale why the Struct::Member syntax is disallowed.
AFAIK, it will be allowed in the next standard.
On 2 Sep, 22:42, petschy <pets...@gmail. comwrote:
Hello All,
I confronted recently with the fact that the size of a struct member
can't be determined with sizeof(Struct:: Member). I'm aware of the
alternative methods to do this, however, I'm interested in the
rationale why the Struct::Member syntax is disallowed.
Thanks, P
Hi. As Juha pointed out, this is already in the draft for the next
standard, but that does not really answer your question :).
You may find these links interesting: http://www.open-std.org/JTC1/sc22/wg...fects.html#198 http://www.open-std.org/jtc1/sc22/wg...007/n2253.html
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