Constant member of a class

[Anarki]

#include <iostream>
using namespace std;

class ConstantMember
{
const int m_const;
public:
ConstantMember( int cons = 10):m_const(con s){}
int getConst() const{ return m_const;}
};

int main()
{
ConstantMember X;//(20);
cout << X.getConst();
return 0;
}

the above is a program that was compiled & linked using g++. Is there
any other way to initialise a constant member variable using
constructor while creating objects?

[Ian Collins]

Anarki wrote:

On Jul 14, 3:16 pm, Ian Collins <[e-mail] mwrote:

>You used an initialiser list.

i understand i used initialiser list but whats happening inside the
initialiser list? What does the compiler do when it see the
initialiser list. I think u didn't get what i meant. i explain a bit
more what's the difference between a normal constructor and
constructor that uses initialiser list.

What does you book tell you? This is pretty basic stuff. If you want
to see exactly what your compiler does, look at the generated assembler.

--
Ian Collins.

[Anarki]

On Jul 15, 1:08*am, Ian Collins <[e-mail] mwrote:

Anarki wrote:

On Jul 14, 3:16 pm, Ian Collins <[e-mail] mwrote:

You used an initialiser list.

i understand i used initialiser list but whats happening inside the
initialiser list? What does the compiler do when it see the
initialiser list. I think u didn't get what i meant. i explain a bit
more what's the difference between a normal constructor and
constructor that uses initialiser list.

What does you book tell you? *This is pretty basic stuff. *If you want
to see exactly what your compiler does, look at the generated assembler.

--
Ian Collins.

Sorry Ian am not a good programmer. I dunno how to get my hands on the
generated assembler and if at all i get my hands on it i dont think i
can understand it. Anyways i am gonna search for the stuff Puppet_sock
said about utab.

[Anarki]

Did u mean his post in this thread? if so

Does it really mean that initialization of constant member variable
occurs before the execution of constructor(usi ng initialiser list).

Again, does that mean a member variable of a object get initialized
even before the object is constructed?

Clearing basics of C++ looks real chaos(for me) :)

[Ian Collins]

Anarki wrote:

Did u mean his post in this thread? if so

Please don't used txt speak on Usenet.

Does it really mean that initialization of constant member variable
occurs before the execution of constructor(usi ng initialiser list).

Yes, members in the initialisation list are initialised before the body
of the constructor is run.

Again, does that mean a member variable of a object get initialized
even before the object is constructed?

No, the initialisation is one phase of the object's construction.

--
Ian Collins.