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Help avoid goto

// return early if all points are the same
for(int i=1; i<n; i++)
if(y[i] != y[0]) goto SKIP;
return;
SKIP:

Can someone help me with an alternative to this snippet that avoids
goto? Without introducing a new variable?
Jun 27 '08
21 1442


spasmous wrote:
// return early if all points are the same
for(int i=1; i<n; i++)
if(y[i] != y[0]) goto SKIP;
return;
SKIP:

Can someone help me with an alternative to this snippet that avoids
goto? Without introducing a new variable?
for(int i=1; i<n; i++)
if(y[i] == y[0]) return;
w..
Jun 27 '08 #21
All, quite correct missed the extent of the for loop. My bad.

w..
Bill Leary wrote:
"Walter Banks" <wa****@bytecra ft.comwrote in message
news:48******** *******@bytecra ft.com...
spasmous wrote:

Assuming 'n' = 5 and y[0] = 9, y[1] = 9, y[2] = 9, y[3] = 99, y[4] = 9
// return early if all points are the same
for(int i=1; i<n; i++)
if(y[i] != y[0]) goto SKIP;
return;
SKIP:

This will not return. It will goto SKIP when i = 3.
Can someone help me with an alternative to this snippet that avoids
goto? Without introducing a new variable?
for(int i=1; i<n; i++)
if(y[i] == y[0]) return;

But this will return when i = 1.

- Bill
Jun 27 '08 #22

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