I could not get this const before a function declaration

[parag_paul]

I understand that a const qualifier after the function declaration
makes it a const function for the class.

Like

int func1 const ( double, long int );

Now what is the purpose of the following
const int func1 const ( double, long int );
What is the purpose of the const before the declaration

-Parag

[Jim Langston]

<pa********@hot mail.comwrote in message
news:f0******** *************** ***********@i18 g2000prn.google groups.com...

>I understand that a const qualifier after the function declaration
makes it a const function for the class.

Like

int func1 const ( double, long int );

Actualy, it's like this:

int func1 ( double, long int ) const;

Now what is the purpose of the following
const int func1 const ( double, long int );

const int func1 ( double, long int ) const;

would be a constant function that returns a constant integer. Really not
making much sense, usually a const returned value is a reference or pointer
such as:

const int & func1 ( double, long int ) const;
or
const int* func1 ( double, long int ) const;

What is the purpose of the const before the declaration

[James Kanze]

On Jun 16, 7:44 am, "Jim Langston" <tazmas...@rock etmail.comwrote :

<parag_p...@hot mail.comwrote in message

news:f0******** *************** ***********@i18 g2000prn.google groups.com...

I understand that a const qualifier after the function
declaration makes it a const function for the class.

Like

int func1 const ( double, long int );

Actualy, it's like this:

int func1 ( double, long int ) const;

Now what is the purpose of the following
const int func1 const ( double, long int );

const int func1 ( double, long int ) const;

would be a constant function that returns a constant integer.
Really not making much sense,

Not much sense, since const-ness doesn't apply to rvalues of
non-class type. It is reasonable for a class type.

--
James Kanze (GABI Software) email:ja******* **@gmail.com
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