fast array copy c++

[fr33host]

Dear developers,
I have a question. Is there a faster array copy than a for loop. What
would you suggest for this code sample?

void get(char* src, char* dest, int i) {
for (int j = 0; j < recordLen; j++, i++) {
dest[j] = src[i];
}
}

Thank you for your answers.

[Pete Becker]

On 2008-05-21 08:46:29 -0400, fr33host <fr******@gmail .comsaid:

Dear developers,
I have a question. Is there a faster array copy than a for loop. What
would you suggest for this code sample?

void get(char* src, char* dest, int i) {
for (int j = 0; j < recordLen; j++, i++) {
dest[j] = src[i];
}
}

Thank you for your answers.

memcpy.

--
Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)

[utab]

On Wed, 21 May 2008 05:46:29 -0700, fr33host wrote:

Dear developers,
I have a question. Is there a faster array copy than a for loop. What
would you suggest for this code sample?

void get(char* src, char* dest, int i) {
for (int j = 0; j < recordLen; j++, i++) {
dest[j] = src[i];
}
}

Thank you for int main()

An option:

std::string source("COPY THIS STRING WITH STL COPY");
std::string dest;
copy(source.beg in(),source.end (),back_inserte r(dest));
std::cout << dest << std::endl;
return 0;

--
Umut

[Zeppe]

utab wrote:

On Wed, 21 May 2008 05:46:29 -0700, fr33host wrote:

>Dear developers,
I have a question. Is there a faster array copy than a for loop. What
would you suggest for this code sample?

void get(char* src, char* dest, int i) {
for (int j = 0; j < recordLen; j++, i++) {
dest[j] = src[i];
}
}

Thank you for int main()

An option:

std::string source("COPY THIS STRING WITH STL COPY");
std::string dest;
copy(source.beg in(),source.end (),back_inserte r(dest));
std::cout << dest << std::endl;
return 0;

this is slower because it doesn't take advantage of knowing the size of
the destination in advance.

An STL implementation of the for cycle is:

std::fill(src, src + recordLen, dest);

Best wishes,

Zeppe

[utab]

On Wed, 21 May 2008 14:05:28 +0100, Zeppe wrote:

utab wrote:

>On Wed, 21 May 2008 05:46:29 -0700, fr33host wrote:

>>Dear developers,
I have a question. Is there a faster array copy than a for loop. What
would you suggest for this code sample?

void get(char* src, char* dest, int i) {
for (int j = 0; j < recordLen; j++, i++) {
dest[j] = src[i];
}
}

Thank you for int main()

An option:

std::string source("COPY THIS STRING WITH STL COPY");
std::string dest;
copy(source.beg in(),source.end (),back_inserte r(dest));
std::cout << dest << std::endl;
return 0;

this is slower because it doesn't take advantage of knowing the size of
the destination in advance.

An STL implementation of the for cycle is:

std::fill(src, src + recordLen, dest);

Best wishes,

Zeppe

Thx for the reminder!

--
Umut

[Pete Becker]

On 2008-05-21 09:05:28 -0400, Zeppe
<ze***@remove.a ll.this.long.co mment.yahoo.its aid:

utab wrote:

>On Wed, 21 May 2008 05:46:29 -0700, fr33host wrote:

>>Dear developers,
I have a question. Is there a faster array copy than a for loop. What
would you suggest for this code sample?

void get(char* src, char* dest, int i) {
for (int j = 0; j < recordLen; j++, i++) {
dest[j] = src[i];
}
}

Thank you for int main()

An option:

std::string source("COPY THIS STRING WITH STL COPY");
std::string dest;
copy(source.beg in(),source.end (),back_inserte r(dest));
std::cout << dest << std::endl;
return 0;

this is slower because it doesn't take advantage of knowing the size of
the destination in advance.

An STL implementation of the for cycle is:

std::fill(src, src + recordLen, dest);

fill takes a value, not an iterator, as its third argument.
std::unitialize d_copy or std::copy would work, depending on whether the
destination is initialized (although that's not really an issue for
char values). memcpy also works fine, without having to decide whether
the target is initialized or whether that matters.

--
Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)

[Matthias Pfeifer]

Zeppe wrote:

>this is slower because it doesn't take advantage of knowing the size of
the destination in advance.

An STL implementation of the for cycle is:

std::fill(src, src + recordLen, dest);

I am also interested in an STL implementation of the mentioned for cycle

>>void get(char* src, char* dest, int i) {
for (int j = 0; j < recordLen; j++, i++) {
dest[j] = src[i];
}
}

and that takes advantage of knowing the size of the destination in
advance, but std::fill does not seem to do the trick for me. std::fill
stores the value dest at [src, src+recordLen). Or am I mistaken?

Matthias

[Frank Birbacher]

Hi!

Zeppe schrieb:

utab wrote:

> std::string source("COPY THIS STRING WITH STL COPY");
std::string dest;
copy(source.beg in(),source.end (),back_inserte r(dest));
std::cout << dest << std::endl;
return 0;

this is slower because it doesn't take advantage of knowing the size of
the destination in advance.

Well:
std::string dest(source.beg in(), source.end());

Or just:
std::string dest = source;

(which sometimes ends up to do no copying at all)

:)
Regards, Frank