Hi there,
I am dealing with the following problem:
I need to convert a std::vector<T(w here T can be any interget
type: char, short, ushort) by applying a linear transform (a,b),
following;
output[i] = a*input[i] + b (a & b are floating point type)
Since memory space is important, I am trying to divide the problem
in subcases. Basically
1. If a or b is float then the output vector need to be declared as
vector<float(in put vector is at most 16bits integer type)
2. Is a & b are integer I need to compute the min/max of the input
scalar type, apply the transform and check the output interval to find
which C type is the best match.
Since this look like boilerplate code, I was wondering if there was
anything I could reuse (other than just numeric_limits to find the min
max). Even just the interval calculation is tricky, although in my
case I can just cast eveyrthing to double since I am dealing with at
most 32bits calculation.
thanks for comments,
-Mathieu 1 1827
On Fri, 25 Apr 2008 15:52:01 +0200, mathieu <ma************ ***@gmail.com
wrote:
Hi there,
I am dealing with the following problem:
I need to convert a std::vector<T(w here T can be any interget
type: char, short, ushort) by applying a linear transform (a,b),
following;
output[i] = a*input[i] + b (a & b are floating point type)
Since memory space is important, I am trying to divide the problem
in subcases. Basically
1. If a or b is float then the output vector need to be declared as
vector<float(in put vector is at most 16bits integer type)
2. Is a & b are integer I need to compute the min/max of the input
scalar type, apply the transform and check the output interval to find
which C type is the best match.
Since this look like boilerplate code, I was wondering if there was
anything I could reuse (other than just numeric_limits to find the min
max). Even just the interval calculation is tricky, although in my
case I can just cast eveyrthing to double since I am dealing with at
most 32bits calculation.
thanks for comments,
-Mathieu
May be you should use std::valarray. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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