i have a question
please refer below..
Example:
#include <stdio.h>
int main() {
printf("%6.1f", 123456.123456);
printf("\n%6.2f ", 123456.123456);
printf("\n%6.3f ", 123456.123456);
printf("\n%6.4f ", 123456.123456);
}
output :
123456.1
123456.12
123456.123
123456.1235
at last output the result was 123456.1235 because it was rounded up.
How to display this value by not rounding up?
like 123456.1234 ?
1 3743
Formatted string conversions will always round as far as I know. The only way would be to truncate all decimals beyond the 4th: -
#include <math.h>
-
double truncate(const double val, const int d)
-
{
-
double rval = val * pow(10,d);
-
rval = (double) floor(rval);
-
return rval / pow(10,d);
-
}
-
-
int main()
-
{
-
double r =1.23456;
-
printf("r = %f, r_4 = %1.4f, r_4t = %1.4f\n",r,r,truncate(r,4));
-
return 0;
-
}
-
-
// Result: r = 1.23456, r_4 = 1.2346, r_4t = 1.2345
-
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