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read and store from unknown file name

Hi! I need to read and store data from a file, but I don't the name of
it; Is this code correct and is there a better way to do this thing??
int main()
{
cout << " type file name:"
char * name;
cin >name;

ifstream indata;
int num1; // variables for input values
int num2;
int num3;
indata.open(nam e); // opens the file
if(!indata) { // file couldn't be opened
cerr << "Error: file could not be opened" << endl;
exit(1);
}
indata >num1;
indata >num2;
indata >num3;
}
Mar 1 '08 #1
4 7958
carmelo wrote:
Hi! I need to read and store data from a file, but I don't the name of
it; Is this code correct and is there a better way to do this thing??
Define "better".

It sounds like the filename is unknown at compile time, but known at run
time. There are a few ways you could get the name, a few include:
1. Accept filename as run time paramater. I.e.
myprog filename.ext
2. Accept the filename as user input
3. Accept the file through std::cin using OS piping.
4. Accept the filename through some other method (graphical input, stored in
a file, etc..)

It depends on what you mean by "better".
int main()
{
cout << " type file name:"
char * name;
cin >name;
This is an error. name is an uninitialied pointer to a character. Yet you
never allocated any memmory for it, so it points .. somewhere. Anywhere.
But not to anything valid. Most likely when the program hits the cin >>
name a run time error will occur as cin attempts to write to memory your
program doesn't "own". Better is:

std::string name;
std::getline( std::cin, name );

getline is better than >in this case because getline will allow a space,
>will stop when it hits the first space leaving the remainder in the
buffer.
ifstream indata;
Might as well just open it here.

std::ifstream indata( name );
int num1; // variables for input values
int num2;
int num3;
indata.open(nam e); // opens the file
So that line isn't needed anymore.
if(!indata) { // file couldn't be opened
cerr << "Error: file could not be opened" << endl;
exit(1);
}
indata >num1;
indata >num2;
indata >num3;
}
You are not checking if the data is valid. Better is:

if ( ! indata >num1 >num2 >num3 )
{
std::cerr << "File dataformat error." << std:;endl;
exit( 1 );
}

// Data is good, proceed
}

--
Jim Langston
ta*******@rocke tmail.com
Mar 1 '08 #2
Jim Langston wrote:
> if(!indata) { // file couldn't be opened
cerr << "Error: file could not be opened" << endl;
exit(1);
}
That would be even better like this:

if(!indata)
{
std::cerr << "Could not open ";
std::perror(nam e.c_str());
exit(EXIT_FAILU RE);
}
Mar 1 '08 #3
On 2008-03-01 11:36, Jim Langston wrote:
carmelo wrote:
>Hi! I need to read and store data from a file, but I don't the name of
it; Is this code correct and is there a better way to do this thing??

Define "better".

It sounds like the filename is unknown at compile time, but known at run
time. There are a few ways you could get the name, a few include:
1. Accept filename as run time paramater. I.e.
myprog filename.ext
2. Accept the filename as user input
3. Accept the file through std::cin using OS piping.
4. Accept the filename through some other method (graphical input, stored in
a file, etc..)

It depends on what you mean by "better".
>int main()
{
cout << " type file name:"
char * name;
cin >name;

This is an error. name is an uninitialied pointer to a character. Yet you
never allocated any memmory for it, so it points .. somewhere. Anywhere.
But not to anything valid. Most likely when the program hits the cin >>
name a run time error will occur as cin attempts to write to memory your
program doesn't "own". Better is:

std::string name;
std::getline( std::cin, name );

getline is better than >in this case because getline will allow a space,
>will stop when it hits the first space leaving the remainder in the
buffer.
> ifstream indata;

Might as well just open it here.

std::ifstream indata( name );
std::ifstream indata(name.c_s tr());

I can't believe that they missed this in the current standard, but at
least it is fixed in the next.

--
Erik Wikström
Mar 1 '08 #4
Erik Wikström wrote:
On 2008-03-01 11:36, Jim Langston wrote:
>carmelo wrote:
>>Hi! I need to read and store data from a file, but I don't the name
of it; Is this code correct and is there a better way to do this
thing??

Define "better".

It sounds like the filename is unknown at compile time, but known at
run time. There are a few ways you could get the name, a few
include:
1. Accept filename as run time paramater. I.e.
myprog filename.ext
2. Accept the filename as user input
3. Accept the file through std::cin using OS piping.
4. Accept the filename through some other method (graphical input,
stored in a file, etc..)

It depends on what you mean by "better".
>>int main()
{
cout << " type file name:"
char * name;
cin >name;

This is an error. name is an uninitialied pointer to a character.
Yet you never allocated any memmory for it, so it points ..
somewhere. Anywhere. But not to anything valid. Most likely when
the program hits the cin >name a run time error will occur as cin
attempts to write to memory your program doesn't "own". Better is:

std::string name;
std::getline ( std::cin, name );

getline is better than >in this case because getline will allow a
space, >will stop when it hits the first space leaving the
remainder in the buffer.
>> ifstream indata;

Might as well just open it here.

std::ifstrea m indata( name );

std::ifstream indata(name.c_s tr());

I can't believe that they missed this in the current standard, but at
least it is fixed in the next.
Oh, yeah. I forgot that ifstream takes a char* and not a std::string. I
sure hope they fix it.

--
Jim Langston
ta*******@rocke tmail.com
Mar 2 '08 #5

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