What's Happening Here - Program Prints Empty Array?

[sarandnl08]

Hi all,

I can't find any problem in this program, i getting empty string as output, why?
what happening here any one help?

int main() 
{ 
        char *p1=“name”; 
        char *p2; 
        p2=(char*)malloc(20); 
        memset (p2, 0, 20); 
        while(*p2++ = *p1++); 
        printf(“%s\n”,p2); 
      return 0;
}

[Ganon11]

Because you are incrementing the pointer as you go, when you finish copying, your pointer looks like this:

p2 ----------------------
                        V
| n | a | m | e | \0 | some more memory |

It will point just after the string you've finished copying.

[sarandnl08]

Because you are incrementing the pointer as you go, when you finish copying, your pointer looks like this:

p2 ----------------------
                        V
| n | a | m | e | \0 | some more memory |

It will point just after the string you've finished copying.

Ya i understood, Thank you very much for your help.