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A program which would print out it's own source code - possible ornot?


Is it possible to write a program which would print out it's own
source code, using C++?
Jan 23 '08
21 3592
On Thu, 24 Jan 2008 20:03:20 +0100, Pascal Bourguignon wrote:
Puppet_Sock <pu*********@ho tmail.comwrites :
>On Jan 23, 6:15Â*am, mikha...@gmail. com wrote:
>>Is it possible to write a program which would print out it's own
source code, using C++?

That's old. The trick is to get the compiler to spit out the entire
source code from messages produced during compilation.

Then it wouldn't be the program that would print out its own source
code, it would be the compiler.
Right. So if you ran a compiled executable of a program that "prints out
its own source code" then I guess it wouldn't be the program that prints
out its own source code, it would be the run-time system.

--
Lionel B
Jan 25 '08 #21
Matt wrote:
>
I looked at some of those examples of a quine the other day. It looked like
there was a constraint where you could not have any input files. So, a
decompliler that took itself as input would not be legal.
The other thing I noticed is they seem to cheat by using printf. Why is it
legal to use external sources in libraries and not also print the source for
those libraries?

Interesting question. However any standard library headers #included, in
reality they can be like a switch, with no actual header file existing.
Jan 25 '08 #22

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