Check if virtual function has been overloaded

[Mark]

Hi,

I have an abstract class which I want my other classes to inherit
from. In the constructor of the abstract class I want to check if
certain virtual functions have been overloaded or not. Is this
possible?

For example, let's say I have

class Base {
public:
virtual void display();
};

class Parent: public: Base {
public:
void display()
}

Then what I want to do is this:

Base::Base() {
if(Parent class has defined display) {
// do something
} else {
// do something else
}
}

[Salt_Peter]

On Dec 27, 8:53 pm, Mark <mnbaya...@gmai l.comwrote:

Hi,

I have an abstract class which I want my other classes to inherit
from. In the constructor of the abstract class I want to check if
certain virtual functions have been overloaded or not. Is this
possible?

Its not an overload, its an override.

>
For example, let's say I have

class Base {
public:
virtual void display();

};

class Parent: public: Base {

class Parent : public Base
{

public:
void display()

}

;

>
Then what I want to do is this:

Base::Base() {
if(Parent class has defined display) {
// do something} else {

// do something else

}
}

The situation you describe suggests a design problem. If Base needs to
know what interface Parent has, then the variation in Base should
really be in Parent.
That or you need an overload of Base's constructor (not override).
Override means hide, overload means supply an alternate signature.

silly example:

class Base
{
bool has_override;
public:
Base() : has_override(fa lse) { }
Base(bool b) : has_override(b) { do something(); }
virtual void display() const { }
private:
void do_something()
{
if(has_override )
// do this
else
// do that
}
};

class Parent : public Base
{
public:
Parent() : Base(true) { }
void display() const { }
};

[Dave Rahardja]

On 2007-12-27 19:53:48 -0600, Mark <mn*******@gmai l.comsaid:

Hi,

I have an abstract class which I want my other classes to inherit
from. In the constructor of the abstract class I want to check if
certain virtual functions have been overloaded or not. Is this
possible?

Why do you want to do this?

-dr

[Mark]

On Dec 27, 7:44 pm, Salt_Peter <pj_h...@yahoo. comwrote:

On Dec 27, 8:53 pm, Mark <mnbaya...@gmai l.comwrote:

Hi,

I have an abstract class which I want my other classes to inherit
from. In the constructor of the abstract class I want to check if
certain virtual functions have been overloaded or not. Is this
possible?

Its not an overload, its an override.

For example, let's say I have

class Base {
public:
virtual void display();

};

class Parent: public: Base {

class Parent : public Base
{

public:
void display()

}

;

Then what I want to do is this:

Base::Base() {
if(Parent class has defined display) {
// do something} else {

// do something else

}
}

The situation you describe suggests a design problem. If Base needs to
know what interface Parent has, then the variation in Base should
really be in Parent.
That or you need an overload of Base's constructor (not override).
Override means hide, overload means supply an alternate signature.

silly example:

class Base
{
bool has_override;
public:
Base() : has_override(fa lse) { }
Base(bool b) : has_override(b) { do something(); }
virtual void display() const { }
private:
void do_something()
{
if(has_override )
// do this
else
// do that
}

};

class Parent : public Base
{
public:
Parent() : Base(true) { }
void display() const { }

};

Yeah... I realized I meant "override" just after posting it, but it's
kind of impossible to edit.
So I'd have to use booleans then? I was hoping I wouldn't...beca use
then I need about 10, and it just gets messy. Oh well, thanks.

[Mark]

On Dec 27, 9:50 pm, Dave Rahardja
<drahardja.plac [e-mail]. pobox.comwrote:

On 2007-12-27 19:53:48 -0600, Mark <mnbaya...@gmai l.comsaid:

Hi,

I have an abstract class which I want my other classes to inherit
from. In the constructor of the abstract class I want to check if
certain virtual functions have been overloaded or not. Is this
possible?

Why do you want to do this?

-dr

Well... if you're curious.

If the Parent class has defined the function, I want to use that
function. If the Parent class has NOT defined the function, I *don't*
want to use the Base class' function, instead, I want to re-route to
another function in a stack. If I'm going to re-route it, I want to
pop an item off the stack, but then I pop an item off the stack in the
destructor, and I don't want to pop it off twice... so... I need to
know whether or not it's already been popped off. Yes, I could use
booleans, but I was hoping there was a more elegant way. In fact... I
did find another way that could potentially stop some future problems
I didn't originally anticipate.

That problem didn't really make a heck of a lot of sense, but I'd have
to explain most of my project before it would make any sense at all.

[Salt_Peter]

On Dec 28, 1:03 am, Mark <mnbaya...@gmai l.comwrote:

On Dec 27, 7:44 pm, Salt_Peter <pj_h...@yahoo. comwrote:

On Dec 27, 8:53 pm, Mark <mnbaya...@gmai l.comwrote:

Hi,

I have an abstract class which I want my other classes to inherit
from. In the constructor of the abstract class I want to check if
certain virtual functions have been overloaded or not. Is this
possible?

Its not an overload, its an override.

For example, let's say I have

class Base {
public:
virtual void display();

};

class Parent: public: Base {

class Parent : public Base
{

public:
void display()

}

;

Then what I want to do is this:

Base::Base() {
if(Parent class has defined display) {
// do something} else {

// do something else

}
}

The situation you describe suggests a design problem. If Base needs to
know what interface Parent has, then the variation in Base should
really be in Parent.
That or you need an overload of Base's constructor (not override).
Override means hide, overload means supply an alternate signature.

silly example:

class Base
{
bool has_override;
public:
Base() : has_override(fa lse) { }
Base(bool b) : has_override(b) { do something(); }
virtual void display() const { }
private:
void do_something()
{
if(has_override )
// do this
else
// do that
}

};

class Parent : public Base
{
public:
Parent() : Base(true) { }
void display() const { }

};

Yeah... I realized I meant "override" just after posting it, but it's
kind of impossible to edit.
So I'd have to use booleans then? I was hoping I wouldn't...beca use
then I need about 10, and it just gets messy. Oh well, thanks.

You don't have to. The boolean is a solution akin to a concept_check.

1) You want Parent::display () to be called when its available
2) when its not, you don't want to process Base::display()
3) you'ld like an alternate function to be processed instead

I'ld like to point out that Base::display() has complete access to the
hierarchy's interface.
It can call any member function it has access to with respect to
override rules.
A Parent knows its a Parent, there is no need to tell it.

So lets see what happens with no override...

#include<iostre am>

class Base
{
public:
Base() { }
virtual ~Base() { }
virtual void display()
{
do_something();
}
private:
virtual void do_something()
{
std::cout << "Base::do_somet hing()\n";
}
};

class Parent : public Base
{
public:
Parent() { }
// void display() { }
void do_something()
{
std::cout << "Parent::do_som ething()\n";
}
};

int main()
{
Parent parent;
parent.display( );
}

/*
Parent::do_some thing()
*/

[Pavel Shved]

On 28 ÄÅË, 04:53, Mark <mnbaya...@gmai l.comwrote:

>
Then what I want to do is this:

Base::Base() {
if(Parent class has defined display) {
// do something} else {

// do something else

}
}

A rude, ugly misconception. The class' constructor doesn't and must
not know that class is or even can ever be derived. At the stage of
constructing Base we do not know whether it is `in-charge' or is not.
This stuff is left for compilers and user - you - have to _create_
every class like a final one.

I've underlined `create' word because, in opposite, the same doesn't
hold for destroying. So you can provide a mecahnism of informing base
class whether he should `pop item from a stack' in destructor. Just
add a corresponding boolean being set in Parent's virtual destructor.
And that re-routing is done by default in Base's virtual function
`default' body.

[Dave Rahardja]

On 2007-12-28 00:12:40 -0600, Mark <mn*******@gmai l.comsaid:

On Dec 27, 9:50 pm, Dave Rahardja
<drahardja.plac [e-mail]. pobox.comwrote:

>On 2007-12-27 19:53:48 -0600, Mark <mnbaya...@gmai l.comsaid:

>>Hi,

>>I have an abstract class which I want my other classes to inherit
from. In the constructor of the abstract class I want to check if
certain virtual functions have been overloaded or not. Is this
possible?

Why do you want to do this?

-dr

Well... if you're curious.

If the Parent class has defined the function, I want to use that
function. If the Parent class has NOT defined the function, I *don't*
want to use the Base class' function, instead, I want to re-route to
another function in a stack. If I'm going to re-route it, I want to
pop an item off the stack, but then I pop an item off the stack in the
destructor, and I don't want to pop it off twice... so... I need to
know whether or not it's already been popped off. Yes, I could use
booleans, but I was hoping there was a more elegant way. In fact... I
did find another way that could potentially stop some future problems
I didn't originally anticipate.

That problem didn't really make a heck of a lot of sense, but I'd have
to explain most of my project before it would make any sense at all.

You have a design problem here. The fact that Base needs to know if
Parent has overridden a virtual function is indicative of a
pathological dependency.

Try looking for a different way to segregate your algorithm. Your Base
class should be a complete class, independent of any potential derived
classes. I suspect that what you'd have to do is to create a different
(or additional) virtual functions, so that Parent can simply extend,
and not modify, Base's management of the pop/no-pop state.

-dr