Quick sort

[Rerun05]

I have a quick sort that reads in data from a file. I know there is something wrong with the partition part of my quick sort and i know exactly what line of code it is. I keep getting the Error C2664: Cannot Convert Parameter 1 from 'x' to 'y'. now thats not exactly what is says but I will show the line of code that it occurs on.

swap(low,(low + high)/2);
 

it tells me that it cannot convert pararmeter 2 from 'int' to 'int &'
Any help would be greatly appreciated, if you need more info just let me know

[scruggsy]

I have a quick sort that reads in data from a file. I know there is something wrong with the partition part of my quick sort and i know exactly what line of code it is. I keep getting the Error C2664: Cannot Convert Parameter 1 from 'x' to 'y'. now thats not exactly what is says but I will show the line of code that it occurs on.

swap(low,(low + high)/2);
 

it tells me that it cannot convert pararmeter 2 from 'int' to 'int &'
Any help would be greatly appreciated, if you need more info just let me know

Your function expects a second parameter of type int&
By calculating the result of a division, you're trying to pass a value - of type int - not a reference of type int&, hence the error.
If you were to do:

int param2 = (low+high) / 2;
swa0(low, param2);

....this would solve the problem. So would changing the function header to take a value instead of a reference.

[weaknessforcats]

swap(low,(low + high)/2);

Fifty dollars says you are using namespace std.

That means you are tripping over std::swap.

Put your swap in tyour own namespace and call it with your namespace name.

(and stop using namespace std. Only teachers do that becuse they never get bit).