Hi everyone,
I wanted to run the following loop,
and enter y everytime (I expected that it will ask
me to enter y for 5 time), but just after 3 times program terminates.
what is the error??
#include <stdio.h>
int main ()
{
char ch;
int j=0;
for (j ; j<5 ; j++)
{
printf("Please enter the input character :\n\n");
scanf("%c", &ch);
printf("You have entered : %c \n\n" , ch);
if (ch == 'y' || ch == 'Y')
printf("HIIIIII III \n");
}
return 0;
} 5 14454
<j.*******@goog lemail.comwrote in message
news:3f******** *************** ***********@v4g 2000hsf.googleg roups.com...
Hi everyone,
I wanted to run the following loop,
and enter y everytime (I expected that it will ask
me to enter y for 5 time), but just after 3 times program terminates.
what is the error??
#include <stdio.h>
int main ()
{
char ch;
int j=0;
for (j ; j<5 ; j++)
{
printf("Please enter the input character :\n\n");
scanf("%c", &ch);
printf("You have entered : %c \n\n" , ch);
Change the above line to:
printf("You have entered: %c (decimal %d) \n", ch, (int)ch);
and run it again. Look carefully at the results.
>
if (ch == 'y' || ch == 'Y')
printf("HIIIIII III \n");
}
return 0;
}
-Mike
Now it gives following output, but it is not the expected output.
I still could not find what the problem is.
Please enter the input character :
y
You have entered: y (decimal 121)
HIIIIIIIII
Please enter the input character :
You have entered:
(decimal 10)
Please enter the input character :
y
You have entered: y (decimal 121)
HIIIIIIIII
Please enter the input character :
You have entered:
(decimal 10)
Please enter the input character :
y
You have entered: y (decimal 121)
HIIIIIIIII
On Dec 5, 1:29 am, "Mike Wahler" <mkwah...@mkwah ler.netwrote:
<j.smit...@goog lemail.comwrote in message
news:3f******** *************** ***********@v4g 2000hsf.googleg roups.com...
Hi everyone,
I wanted to run the following loop,
and enter y everytime (I expected that it will ask
me to enter y for 5 time), but just after 3 times program terminates.
what is the error??
#include <stdio.h>
int main ()
{
char ch;
int j=0;
for (j ; j<5 ; j++)
{
printf("Please enter the input character :\n\n");
scanf("%c", &ch);
printf("You have entered : %c \n\n" , ch);
Change the above line to:
printf("You have entered: %c (decimal %d) \n", ch, (int)ch);
and run it again. Look carefully at the results.
if (ch == 'y' || ch == 'Y')
printf("HIIIIII III \n");
}
return 0;
}
-Mike
"j.*******@goog lemail.com" <j.*******@goog lemail.comwrite s:
Now it gives following output, but it is not the expected output.
I still could not find what the problem is.
This is question 12.18b of the C FAQ: http://c-faq.com/stdio/scanfc.html
Please enter the input character :
y
You have entered: y (decimal 121)
HIIIIIIIII
Please enter the input character :
You have entered:
(decimal 10)
Please enter the input character :
<snip similar>
PS. Please snip your replies to include on the parts you are
commenting on.
--
Ben.
On Dec 5, 2:00 am, Ben Bacarisse <ben.use...@bsb .me.ukwrote:
"j.smit...@goog lemail.com" <j.smit...@goog lemail.comwrite s:
Now it gives following output, but it is not the expected output.
I still could not find what the problem is.
This is question 12.18b of the C FAQ:
http://c-faq.com/stdio/scanfc.html
Please enter the input character :
y
You have entered: y (decimal 121)
HIIIIIIIII
Please enter the input character :
You have entered:
(decimal 10)
Please enter the input character :
<snip similar>
PS. Please snip your replies to include on the parts you are
commenting on.
--
Ben.
Hello all,
Still I could not solve the problem mentioned.
Do anyone can tell "if I want to run for loop from 1 to 5, everytime
it ask user to enter a character , and if that
character is same with y, then print "Hello" ".
Thank you.
smith j.*******@googl email.com wrote:
What part of
>PS. Please snip your replies to include on the parts you are commenting on.
didn't you understand?
Still I could not solve the problem mentioned.
Then you didn't read the FAQ carefully enough.
Do anyone can tell "if I want to run for loop from 1 to 5, everytime
it ask user to enter a character , and if that
character is same with y, then print "Hello" ".
That's a trivial task, but made much harder by your decision
to use scanf().
Try reading the whole of http://c-faq.com/stdio/index.html - question
12.20 is especially relevant.
Then consider rewriting your code without scanf(). This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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