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printf function changes int to char when using format specifier?

Example
printf("I have %d cars. \n", 10);

Is it more correct to say that the printf function doesn't insert the
integer, rather into changes the integer into chars and then inserts
it?

Nov 14 '07 #1
2 1560
On Nov 14, 1:38 pm, vlsidesign <ford...@gmail. comwrote:
Example
printf("I have %d cars. \n", 10);

Is it more correct to say that the printf function doesn't insert the
integer, rather into changes the integer into chars and then inserts
it?
Neither resembles something that is correct.

man printf()
http://linux.die.net/man/3/printf

Or perhaps:
http://www.dinkumware.com/manuals/de...nt%20Functions

Nov 14 '07 #2
vlsidesign wrote:
Example
printf("I have %d cars. \n", 10);

Is it more correct to say that the printf function doesn't insert the
integer, rather into changes the integer into chars and then inserts
it?
printf inserts (into the stdout output stream) a textual representation of the
int value 10.

It doesn't change the integer into anything; 10 is still an integer. Rather, it
computes a sequence of characters {'1', '0'} from the integer.

--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
Looking for software development work in the San Diego area.
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister"
Nov 14 '07 #3

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