program to find the length of the string manually

[goelvivek]

write a program to find the length of the string without using control structures and without using string.h header files???

[PuzzleC]

write likeness a standart strlen function.

Sorry, it is strig.... string str; str.length(); ????

[goelvivek]

but that will use a control structure like
while(s!='\0')
l++;

and we don't have to use that

can is their is method so that we print string and then calculate the pointer position at that time

[PuzzleC]

see above... or convert to char* sl.c_str() and working as a character type

[weaknessforcats]

write a program to find the length of the string without using control structures and without using string.h header files???

A C string is a char array with a \0 as the last character. Just count the characters in the array without counting the \0.

[goelvivek]

A C string is a char array with a \0 as the last character. Just count the characters in the array without counting the \0.

is their is no answer

[PuzzleC]

A C string is a char array with a \0 as the last character. Just count the characters in the array without counting the \0.

what is a type C string?
C++ string
approximate:

cpp
class string
 {
private:                  
 struct ChatT
  {
  ...
  ...
  blablabla;
  };
 ChatT *s;
 int __length;  //<---- private mamber of class string
public:
 int length() { return this->__length; }
 } ;
 

[Studlyami]

when you say the length of the string, does string refer to a variable of string type or is this a character array?

[chazzy69]

If you are using character arrays e.g. char string[256], Then all you have to do is to read each element of the string from the start 0 or 1 until char string[x] = "\0".
You can do this in any loop.

For example, no error checking done

char string[256];
int x;
 
cin>> string; // or physically assign each element e.g. string[1] = a and string[2] =b
 
while (string(x) <> "\0") {
x++;
}
 
cout<< (x-1); // this will give the last value of the string before string(x) = "\0"
 

Hope this helps

[weaknessforcats]

Thre previous 9 posts are riddled with errors:

Originally:

write a program to find the length of the string without using control structures and without using string.h header files???

Using the string.h header file indicates that the OP is interested in C strings which makes the following seem odd:

what is a type C string?
C++ string
approximate:

Code: ( text )
cpp
class string
{
private:
struct ChatT
{
...
...
blablabla;
};
ChatT *s;
int __length; //<---- private mamber of class string
public:
int length() { return this->__length; }
} ;

since there are no classes in C. This is a C++ example, and a poor one, since there is a C++ string class that is part of the C++ Standard Library. But all of that is irrelevant since the OP is interested in a C string.

A C string is an array of char with the last element a binary 0 ('\0').

when you say the length of the string, does string refer to a variable of string type or is this a character array?

The length of a C string is the number of characters counting from the start of the array to (but not including) the \0.

If you are using character arrays e.g. char string[256], Then all you have to do is to read each element of the string from the start 0 or 1 until char string[x] = "\0".
You can do this in any loop.

For example, no error checking done


Code: ( text )
char string[256];
int x;

cin>> string; // or physically assign each element e.g. string[1] = a and string[2] =b

while (string(x) <> "\0") {
x++;
}

cout<< (x-1); // this will give the last value of the string before string(x) = "\0"

There are a lot of errors in this code sample:
1) cin >> string will only fetch a string that has no whitespace in it. Usually, this means you fetch only one word of the input.

2) string[x] = "\0" won't compile. string[x] is a char. "\0" is an empty string. That is, an array with \0 as element[0]. In C and C++ the array name is the address of element[0] so this compares a char to the address of the char \0. The compiler will gag on this.

3) while (string(x) <> "\0") { won't compile. string(x) is a function call to the function string using the argument x. Proably you meant string[x]. However the <> won't work, again that compares a char to the addess of a char. See (2) above.

Now read my Post #5 again and follow the direction exactly.