How is this trivial strncpy implementation

[lovecreatesbea...]

Do I need to repeat inserting '\0' n - strlen(src) times in case
strlen(str) less than n. "C: A reference Manual, 5th" mentions this in
sec 13.3. "K&RC, 2nd" says that insert one '\0' under the same
condition in sec B.3.

Thank you for your time.
/
*************** *************** *************** *************** *************** ****
* copy n characters in string src to dst.

*************** *************** *************** *************** *************** ***/

char *strncpy(char *dst, const char *src, size_t n)
{
char *p = dst;

while (n-- && (*dst++ = *src++))
;
return p;
}

[santosh]

lovecreatesbea. [e-mail] wrote:

Do I need to repeat inserting '\0' n - strlen(src) times in case
strlen(str) less than n.

The Standard strncpy does. You can do whatever you want with your
private variations, but do avoid nameclashes with the Standard library,
and give a better more descriptive name. The Standard has a lot of
constraints, not least of which are historical ones, but you can do
better than cryptic six and seven letter names.

snip

[Ben Pfaff]

"lovecreatesbea [e-mail]" <lo************ ***@gmail.comwr ites:

[about strncpy]

Do I need to repeat inserting '\0' n - strlen(src) times in case
strlen(str) less than n.

Yes, strncpy always writes to every byte in the output buffer.
--
char a[]="\n .CJacehknorstu" ;int putchar(int);in t main(void){unsi gned long b[]
={0x67dffdff,0x 9aa9aa6a,0xa77f fda9,0x7da6aa6a ,0xa67f6aaa,0xa a9aa9f6,0x11f6} ,*p
=b,i=24;for(;p+ =!*p;*p/=4)switch(0[p]&3)case 0:{return 0;for(p--;i--;i--)case+
2:{i++;if(i)bre ak;else default:continu e;if(0)case 1:putchar(a[i&15]);break;}}}