Converting English to Metric and vice versa via pass-by-reference void function.

[socondc22]

Im stuck at this point. The way i was trying to do this was running if statement around my void function and then a else if statement around a different void function but it didnt work... right now i deleted part of what i had but left my skeleton of it there...

 #include <iostream>
using namespace std;
void get_numbers(double& input1, double& input2);
void show_results(double output1, double output2);
 
int main()
{
  char letter;
 
  cout<<"Metric to English and English to Metric converter.\n"
      <<"For Metric to English type m, for Enlish to Metric type E, Type q to quit.\n";
  cin>>letter;
 
     double first_num, second_num;
 
     get_numbers(first_num, second_num);
     show_results(first_num, second_num);
     return 0;
}
 
 
void get_numbers(double& input1, double& input2)
 {
  using namespace std;
  cout<< "Enter first number as meters and second as centimeters.\n";
  cin>> input1
     >> input2;
  input1 = input1 * 3.2808399;
  input2 = input2 * .393700787;
 }
 
 void show_results(double output1, double output2)
 {
  using namespace std;
  cout<< "Feet: "<<output1<<" Inches: "<<output2<<endl;
 }
 

[weaknessforcats]

The way i was trying to do this was running if statement around my void function and then a else if statement around a different void function but it didnt work...

I can't see what your difficulty is when you have deleted the code that caused it.

[pbmods]

Heya, socondc22.

What do you want your code to do? Give an example.
What is your code doing that you don't want it to do? Give an example.
What is your code *not* doing that it is supposed to? Give an example.

[JosAH]

@OP: please don't start two or more threads on this very same topic.

kind regards,

Jos