Creating a struct array in C

[GARiMTO]

Hi there
I'm introducting myself in structures in C
What i'm trying to do, is create a structure with 3 types like name, age, weight, etc, so i typedef a struct
in order to save information for more than one "guy", i must create a struct array so that data could be saved.. and that's where my problem is!
i'll send my code here and hope anyone helps me with solving this!
the real question is, how to make the array, and in the end, print the data that the user entered (like "his name is john and he has 20 years old" / etc etc)

#include <iostream.h> 
#include <stdlib.h> 
#include <stdio.h>
 
typedef struct {
    char name[20];
    int age;
    int weight;
}ANIMAL;
 
 
void main(){
 
 
    ANIMAL * horse;
    ANIMAL * horses_array[2];    // i believe this is wrong
    int count = 0;
    int insert;
    printf("How many Horses do you want to insert?\n");
    scanf("%d",&insert);
 
    horse = (ANIMAL*) malloc(insert*sizeof(ANIMAL));
 
    for (count=0; count<insert; count++){
 
    printf("Enter the name of the horse number %d: \n",count);
    scanf("%s",horse[count].name);
    printf("Enter the age of horse number %d: \n",count);
    scanf("%d",&horse[count].age);
    printf("Enter the weight of horse number %d: \n",count);
    scanf("%d",&horse[count].weight);
 
    }
    printf("The Horse number %d has the name %s",count(???),horse[count].name); // print information about the 1++ horses inserted
 
}

modify as you please!
thanks in advance, peace

[shabinesh]

there is nothing wrong ..you are correct

[GARiMTO]

there is nothing wrong ..you are correct

but how do i creat an struct array?
with int's i make like this:
int a[10];

but with struct ANIMAL, how do i make?
ANIMAL horseArray[2] ? it gives me an error!
help

[weaknessforcats]

but with struct ANIMAL, how do i make?
ANIMAL horseArray[2] ? it gives me an error!

No it doesn't. At least it won't after you hadd the semi-colon at the end of the statement.

This is an array of 2 ANIMAL variables.

However this is not the code in your original post:

ANIMAL * horses_array[2]; // i believe this is wrong

Nothing wrong here either. Except this is an array of two pointers to ANIMAL variables.

Are you confusing a pointer to ANIMAL with the ANIMAL itself?

[Studlyami]

First let me say that I'm not real familiar with malloc, but i know you are allocating memory for the size of the array. The problem i see is you specified the array size as 2 ( Animal Horse_Array[2];) Then allocate memory for a user specified the size then you access elements outside of the original declaration. i.e. that loop would access Horse_Array[8] or Horse_Array[10]. That just seem wrong to me, but it could be different styles.

Heres another way of handle this while using heap memory.

ANIMAL * horse;
    int count = 0;
    int insert;
    printf("How many Horses do you want to insert?\n");
    scanf("%d",&insert);
 
    horse = new ANIMAL[insert];
 
    for (count=0; count<insert; count++){
 
    printf("Enter the name of the horse number %d: \n",count);
    scanf("%s",horse[count].name);
    printf("Enter the age of horse number %d: \n",count);
    scanf("%d",&horse[count].age);
    printf("Enter the weight of horse number %d: \n",count);
    scanf("%d",&horse[count].weight);
 
        }
 
delete [] horse; //must delete the array manually now in order to prevent memory leak
 

[Studlyami]

Sorry about that post up above I didn't read that you were using C. I guess thats what i get for not being observant.