im creating a iterrative server
and i get this error
error: syntax error before numeric constant
and this errors occurs near this line:
int listen(sock,5);
need help
and this is begining of my iterative server
can any one check my code to see if im on the right track: -
#include <sys/types.h>
-
#include <sys/socket.h>
-
#include <netinet/in.h>
-
#include <netdb.h>
-
#include <stdio.h>
-
#include <stdlib.h>
-
#include <string.h> // for strlen()
-
-
#define EOB "$$"
-
#define KB_size 1024
-
int ClientNo = 0;
-
-
int main(void)
-
{
-
int sock;
-
int intPort;
-
int NoClients;
-
int num;
-
int i;
-
char host[80];
-
int mssock; /* fd from accept return */
-
struct sockaddr_in server; /* socket struct for server connection */
-
struct sockaddr_in client; /* socket struct for client connection */
-
int clientLen; /* returned length of client from accept() */
-
int rval; /* return value from read() */
-
char KB_buff[KB_size];
-
-
-
-
sock = sockTCP_create();
-
/* Open a socket, not bound yet. */
-
if ((sock = socket(AF_INET, SOCK_STREAM, 0)) > 0)
-
printf("Opening stream socket \n");
-
-
// Binding a socket //
-
-
printf("Could you Please Enter port: \n");
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fgets(KB_buff, KB_size, stdin);
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intPort = atoi(KB_buff);
-
bzero((char *) &server, sizeof(server));
-
server.sin_family = AF_INET;
-
server.sin_addr.s_addr = INADDR_ANY;
-
server.sin_port = htons(intPort);
-
(bind(sock, (struct sockaddr *) &server, sizeof(server)));
-
printf("Socket has port %hu\n", ntohs(server.sin_port));
-
-
//Listen a socket///
-
int listen(sock,5);
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if (listen < 0)
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printf("Socket is listening");
-
-
//Usess accept function to accept an incoming connection request//
-
-
-
}
3 17090 gpraghuram 1,275
Recognized Expert Top Contributor
Hi,
The error is here -
//Listen a socket///
-
int listen(sock,5); //why there is a int befor listen call.
-
//remove that and the program can compile properly.
-
-
Thanks
Raghuram
Hi,
The problem in 'int listen(sock,5)' is the way it is used.
It should be
int listn;
listn = listen(sock,5)
Hope this will work fine.
Regards,
Chella
thank you very much it worked
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