Copying array to an array, I really thought I knew what was going on.

[DaTurk]

This is probably a very silly, and simple question. If I'm coding in
CLI, and I want to copy an array to an array, not a deep copy, just
something of the nature arr1 = arr2, what is going on?

I assumed the address of the first element is getting copied, so i
essentially have two handles to the same memory. And changes in one
would be reflected in the other.

But what if I have something like this

public value struct MyStruct
{
Int32 MyNumber;
};

array<MyStruct> ^ arr1 = gcnew array<MyStruct( 10);

//We fill the array with 10 MyStruct

array<MyStruct> ^ arr2 = arr1;

Now what do we have here? since it's a value struct, did we
essentially do a deep copy?

[=?ISO-8859-1?Q?Erik_Wikstr=F6m?=]

On 2007-09-10 21:11, DaTurk wrote:

This is probably a very silly, and simple question. If I'm coding in
CLI, and I want to copy an array to an array, not a deep copy, just
something of the nature arr1 = arr2, what is going on?

If you are coding in C++/CLI you are asking in the wrong group. This
group is for discussing C++ (and while C++/CLI might have a name and
syntax similar to C++ they are two very different things). I would
suggest you ask your question in either one of the microsoft.publi c.*
groups, microsoft.publi c.dotnet.langua ges.vc is probably the one you
want. Another good place to ask is forums.microsof t.com

--
Erik Wikström

[Jim Langston]

"DaTurk" <mm******@hotma il.comwrote in message
news:11******** **************@ k79g2000hse.goo glegroups.com.. .

This is probably a very silly, and simple question. If I'm coding in
CLI, and I want to copy an array to an array, not a deep copy, just
something of the nature arr1 = arr2, what is going on?

I assumed the address of the first element is getting copied, so i
essentially have two handles to the same memory. And changes in one
would be reflected in the other.

But what if I have something like this

public value struct MyStruct
{
Int32 MyNumber;
};

array<MyStruct> ^ arr1 = gcnew array<MyStruct( 10);

//We fill the array with 10 MyStruct

array<MyStruct> ^ arr2 = arr1;

Now what do we have here? since it's a value struct, did we
essentially do a deep copy?

Ignoring hte fact that this isn't C++ code but something else (C# maybe?)
and presuming ^ is some type of pointer...

If this code was:

public value struct MyStruct
{
Int32 MyNumber;
};

MyStruct* arr1 = new MyStruct[10];

//We fill the array with 10 MyStruct

MyStruct* arr2 = new MyStruct[10];

You would want to iterate over the array copying elements. The manual
method is:

for ( size_t i = 0; i < 10; ++i )
arr2[i] = arr1[i];

This is a very common task, however, so TPTB added it to the stl with
std::copy

std::copy( arr1.begin(), arr1.end(), std::inserter(a rr2, arr2.end()) );

The syntax for the 3rd parameter of std::copy here may be wrong, but it
should work.

Other than that, ask in a newsgroup related to your language, whatever it
is.