I need to pass a two dimensional matrix to a function. Function gets
int ** but i cannot find appropriate input to function in main.
in main
mdelc(&ar1, 5, 5, 3);
function prototype:
void mdelc(int **ar1, int a, int b, int d) 4 2327
"Dinçay Akçören" <di****@gmail.c omwrote in message
news:11******** **************@ y42g2000hsy.goo glegroups.com.. .
>I need to pass a two dimensional matrix to a function. Function gets
int ** but i cannot find appropriate input to function in main.
in main
mdelc(&ar1, 5, 5, 3);
function prototype:
void mdelc(int **ar1, int a, int b, int d)
int **ar;
ar = malloc(height * sizeof(int *));
for(i=0;i<heigh t;i++)
ar[i] = malloc(width * sizeof(int));
now you can use
ar[y][x] = a; to set up the matrix values
call
mcdecl(ar, 5, 5, 3)
no &. ar is already an int **.
That's probably what the function mdecl is expecting. However it is not
possible to be certain without more information. It might have different
requirements for setting up the matrix.
--
Free games and programming goodies. http://www.personal.leeds.ac.uk/~bgy1mm
On 2 Eylül, 00:38, "Malcolm McLean" <regniz...@btin ternet.comwrote :
"Dinçay Akçören" <din...@gmail.c omwrote in message
news:11******** **************@ y42g2000hsy.goo glegroups.com.. .
I need to pass a two dimensional matrix to a function. Function gets
int ** but i cannot find appropriate input to function in main.
in main
mdelc(&ar1, 5, 5, 3);
function prototype:
void mdelc(int **ar1, int a, int b, int d)
int **ar;
ar = malloc(height * sizeof(int *));
for(i=0;i<heigh t;i++)
ar[i] = malloc(width * sizeof(int));
now you can use
ar[y][x] = a; to set up the matrix values
call
mcdecl(ar, 5, 5, 3)
no &. ar is already an int **.
That's probably what the function mdecl is expecting. However it is not
possible to be certain without more information. It might have different
requirements for setting up the matrix.
--
Free games and programming goodies.http://www.personal.leeds.ac.uk/~bgy1mm
It doesn't work :(
Here is the function
void mdelr(int **arr, int a, int b, int d )
{
int i;
int j;
for (i=0; i<a; i++)
{
for(j=0; j<b; j++)
{
if (i >= d)
arr[i][j] = arr[i+1][j];
if (i == b-1)
arr[i][j] = 0;
}
}
}
arr is a*b matris, row d is deleted, then remaining part is shifted to
left.
"Dinçay Akçören" <di****@gmail.c omwrote in message
news:11******** **************@ r34g2000hsd.goo glegroups.com.. .
On 2 Eylül, 00:38, "Malcolm McLean" <regniz...@btin ternet.comwrote :
"Dinçay Akçören" <din...@gmail.c omwrote in message
news:11******** **************@ y42g2000hsy.goo glegroups.com.. .
I need to pass a two dimensional matrix to a function. Function gets
int ** but i cannot find appropriate input to function in main.
in main
mdelc(&ar1, 5, 5, 3);
function prototype:
void mdelc(int **ar1, int a, int b, int d)
int **ar;
ar = malloc(height * sizeof(int *));
for(i=0;i<heigh t;i++)
ar[i] = malloc(width * sizeof(int));
now you can use
ar[y][x] = a; to set up the matrix values
call
mcdecl(ar, 5, 5, 3)
no &. ar is already an int **.
That's probably what the function mdecl is expecting. However it is not
possible to be certain without more information. It might have different
requirements for setting up the matrix.
--
Free games and programming goodies.http://www.personal.leeds.ac.uk/~bgy1mm
It doesn't work :(
Here is the function
void mdelr(int **arr, int a, int b, int d )
{
int i;
int j;
for (i=0; i<a; i++)
{
for(j=0; j<b; j++)
{
if (i >= d)
arr[i][j] = arr[i+1][j];
if (i == b-1)
arr[i][j] = 0;
}
}
}
arr is a*b matris, row d is deleted, then remaining part is shifted to
left.
>>>>>>>>>
It should work as I described.
arr is a pointer to a list of pointers. arr[i][j] accesses the i th row and
j th column of the matrix.
a and b have to be matrix height and width.
On Sat, 01 Sep 2007 15:38:29 -0700, "Dinçay Akçören"
<di****@gmail.c omwrote:
>On 2 Eylül, 00:38, "Malcolm McLean" <regniz...@btin ternet.comwrote :
>"Dinçay Akçören" <din...@gmail.c omwrote in message
news:11******* *************** @y42g2000hsy.go oglegroups.com. ..
>I need to pass a two dimensional matrix to a function. Function gets
int ** but i cannot find appropriate input to function in main.
in main
mdelc(&ar1, 5, 5, 3);
function prototype:
void mdelc(int **ar1, int a, int b, int d)
int **ar;
ar = malloc(height * sizeof(int *)); for(i=0;i<heig ht;i++) ar[i] = malloc(width * sizeof(int));
now you can use
ar[y][x] = a; to set up the matrix values
call mcdecl(ar, 5, 5, 3) no &. ar is already an int **.
That's probably what the function mdecl is expecting. However it is not possible to be certain without more information. It might have different requirements for setting up the matrix.
-- Free games and programming goodies.http://www.personal.leeds.ac.uk/~bgy1mm It doesn't work :(
Describe doesn't work. Are you getting compiler or linker errors? Are
the results different than what you expect? How.
>Here is the function
Show the code that calls the function. Preferably a compilable unit.
> void mdelr(int **arr, int a, int b, int d )
{
int i;
int j;
for (i=0; i<a; i++)
{
for(j=0; j<b; j++)
{
if (i >= d)
arr[i][j] = arr[i+1][j];
When i = b-1, this invokes undefined behavior by access arr[b][j],
non-existent elements of the array.
You could reverse these two if blocks and make the test on d an else
if.
if (i == b-1)
arr[i][j] = 0;
}
} }
arr is a*b matris, row d is deleted, then remaining part is shifted to left.
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