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Calling base method within aggregation

3 New Member
Hi,
I am trying to solve one problem. I have one object and I create another different object from it (aggregation).
How can I now call methods of first object within the second object?

Here is how I was trying to do it (its obviously wrong):

class second;
class first
{
public:
second s(this); //here i aggregate the second object
first() {};
void test() {cout<<"test"<< endl;}
};

class second
{
public:
secondc(first *f)
{
f->test(); //and from here I'd like to call the f's method
};
};

void main()
{
first *f = new first();
}


Could you plese provide some hints how this can be done (examples would be great).

thanks & greetings
-oneshed
Sep 1 '07 #1
1 1445
weaknessforcats
9,208 Recognized Expert Moderator Expert
The topic is titled Calling Base Method Within Aggregation.

There's no inheritance in your example so there is no base class.

Aggregation means that one object contains other objects not that one object can create other objects. Objects that do that are called Factories.

I guess I'm a little confused as to your question.
Sep 2 '07 #2

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