macros with double pound signs (##)

[davoti]

Hi,

I never truly understand how a macro with ## work in C, for example,
if I define

#define X X##_YZ[2]

what and how does this translated into after compilation?
Can't find similar info. googling, would appreciate some detailed
information.

Thanks in advance.

tom

[Pietro Cerutti]

da****@gmail.co m wrote:

Hi,

I never truly understand how a macro with ## work in C, for example,
if I define

#define X X##_YZ[2]

Not very useful here, actually,

The double pound sign is used for token concatenation:
Example:

#define BUILD_NAME(X,Y) X##.##Y

BUILD_NAME("Big ", "Jim")

translates to:

"Big.Jim"

Thanks in advance.

--
Pietro Cerutti

PGP Public Key:
http://gahr.ch/pgp

[davoti]

On Aug 28, 10:13 am, Pietro Cerutti <[e-mail] ote:

[e-mail] m wrote:

Hi,

I never truly understand how a macro with ## work in C, for example,
if I define

#define X X##_YZ[2]

Not very useful here, actually,

The double pound sign is used for token concatenation:
Example:

#define BUILD_NAME(X,Y) X##.##Y

BUILD_NAME("Big ", "Jim")

translates to:

"Big.Jim"

Thanks in advance.

--
Pietro Cerutti

PGP Public Key:http://gahr.ch/pgp

Thanks for the information, Sometimes it is used before the token,
other time behind it, in your example, can I do like below? What's the
difference?

#define BUILD_NAME(X,Y) ##X.##Y

Thanks again

tom

[Ben Pfaff]

Pietro Cerutti <ga**@gahr.chwr ites:

The double pound sign is used for token concatenation:
Example:

#define BUILD_NAME(X,Y) X##.##Y

BUILD_NAME("Big ", "Jim")

translates to:

"Big.Jim"

I'm pretty sure that it doesn't, actually.

If you want to write code with that effect, you can much more
simply write:
#define BUILD_NAME(X,Y) X "." Y
so that BUILD_NAME("Big ", "Jim") translates to:
"Big" "." "Jim"
which the compiler will then concatenate into a single string,
with the same effect as "Big.Jim".
--
"What is appropriate for the master is not appropriate for the novice.
You must understand the Tao before transcending structure."
--The Tao of Programming

[Pietro Cerutti]

Ben Pfaff wrote:

Pietro Cerutti <ga**@gahr.chwr ites:

>The double pound sign is used for token concatenation:
Example:

#define BUILD_NAME(X,Y) X##.##Y

BUILD_NAME("Bi g", "Jim")

translates to:

"Big.Jim"

I'm pretty sure that it doesn't, actually.

If you want to write code with that effect, you can much more
simply write:
#define BUILD_NAME(X,Y) X "." Y
so that BUILD_NAME("Big ", "Jim") translates to:
"Big" "." "Jim"
which the compiler will then concatenate into a single string,
with the same effect as "Big.Jim".

You are right. I tried to think about the simplest and smallest example
using token concatenation, and I failed miserably ;-)

Next try:

The token created by concatenating X and Y has to be itself a valid token:

#define BUILD_MSG(X) msg_##X

BUILD_MSG(hello )

would translate to

msg_hello

--
Pietro Cerutti

PGP Public Key:
http://gahr.ch/pgp

[Pietro Cerutti]

da****@gmail.co m wrote:

On Aug 28, 10:13 am, Pietro Cerutti <[e-mail] ote:

>dav...@gmail.c om wrote:

>>Hi,
I never truly understand how a macro with ## work in C, for example,
if I define
#define X X##_YZ[2]

Not very useful here, actually,

The double pound sign is used for token concatenation:
Example:

#define BUILD_NAME(X,Y) X##.##Y

BUILD_NAME("Bi g", "Jim")

translates to:

"Big.Jim"

>>Thanks in advance.

--
Pietro Cerutti

PGP Public Key:http://gahr.ch/pgp

Thanks for the information, Sometimes it is used before the token,
other time behind it, in your example, can I do like below? What's the
difference?

Please read my other post, in reply to Ben Pfaff, for corrections on the
explanation :-)

The ## goes on the side you want your token to be pasted:

#define BUILD_NAME(X,Y) ##X.##Y

You have two tokens, X and Y, which you want to concatenate, using a dot
in between
You want the dot to appear AFTER X, and Y appear after the dot
-X ## . ## Y

>
Thanks again

--
Pietro Cerutti

PGP Public Key:
http://gahr.ch/pgp

[karthikbalaguru]

On Aug 28, 10:02 pm, [e-mail] m wrote:

Hi,

I never truly understand how a macro with ## work in C, for example,
if I define

#define X X##_YZ[2]

what and how does this translated into after compilation?
Can't find similar info. googling, would appreciate some detailed
information.

In simple terms - It is for token concatenation / token pasting.
Search using the terms "Token Concatenation in C" or "Token Pasting in
C" or "## in C"

Karthik Balaguru

[Justin Spahr-Summers]

On Aug 28, 12:58 pm, Pietro Cerutti <[e-mail] ote:

#define BUILD_NAME(X,Y) ##X.##Y

You have two tokens, X and Y, which you want to concatenate, using a dot
in between
You want the dot to appear AFTER X, and Y appear after the dot
-X ## . ## Y

Although, to be precise, if you're using the dot to access a structure
member (e.g. somestruct.valu e), no concatenation is needed, as it is
made up of three separate tokens. I'm not sure if token concatenation
would work for constructing floating-point numbers, but I imagine it
potentially could.

[user923005]

On Aug 28, 10:02 am, [e-mail] m wrote:

Hi,

I never truly understand how a macro with ## work in C, for example,
if I define

#define X X##_YZ[2]

what and how does this translated into after compilation?
Can't find similar info. googling, would appreciate some detailed
information.

Do a web search for "Token pasting operator"