pointer to structure array

[estantep]

Hello,

I am having some trouble trying to pass a pointer to an structure
array (as function argument), when executing I get seg faults.

The best I could get out from googling was:

#define MAX_GRAPH 256

typedef struct edge{
long delay;
long bandw;
} edge;

edge link[MAX_GRAPH][MAX_GRAPH];

int print_structure (edge *graph[MAX_GRAPH][MAX_GRAPH]){
int i, j;
for(i=0;i<nodes ;i++){
for(j=0;j<nodes ;j++){
printf("[%d][%d].bandw = %d\t\t", i, j, graph[i][j]->bandw); //
SEG FAULT!
printf("[%d][%d].delay = %d\n", i, j, graph[i][j]->delay);
}
}
return 0;
}
int main(int argc, char* argv[]){

....
print_structure (link);
....
}

Could anybody help me spot the problem?

Thanks,

Paulo

[Ark Khasin]

es******@gmail. com wrote:

Hello,

I am having some trouble trying to pass a pointer to an structure
array (as function argument), when executing I get seg faults.

The best I could get out from googling was:

#define MAX_GRAPH 256

typedef struct edge{
long delay;
long bandw;
} edge;

edge link[MAX_GRAPH][MAX_GRAPH];

int print_structure (edge *graph[MAX_GRAPH][MAX_GRAPH]){
int i, j;
for(i=0;i<nodes ;i++){
for(j=0;j<nodes ;j++){
printf("[%d][%d].bandw = %d\t\t", i, j, graph[i][j]->bandw); //
SEG FAULT!
printf("[%d][%d].delay = %d\n", i, j, graph[i][j]->delay);
}
}
return 0;
}
int main(int argc, char* argv[]){

...
print_structure (link);
...
}

Could anybody help me spot the problem?

Thanks,

Paulo

print_struct is called not according to its type (inferred from its
definition). [Remove the * in the definition]

[pete]

es******@gmail. com wrote:

>
Hello,

I am having some trouble trying to pass a pointer to an structure
array (as function argument), when executing I get seg faults.

The best I could get out from googling was:

#define MAX_GRAPH 256

typedef struct edge{
long delay;
long bandw;
} edge;

edge link[MAX_GRAPH][MAX_GRAPH];

int print_structure (edge *graph[MAX_GRAPH][MAX_GRAPH]){
int i, j;
for(i=0;i<nodes ;i++){
for(j=0;j<nodes ;j++){
printf("[%d][%d].bandw = %d\t\t", i, j, graph[i][j]->bandw); //
SEG FAULT!
printf("[%d][%d].delay = %d\n", i, j, graph[i][j]->delay);
}
}
return 0;
}

int main(int argc, char* argv[]){

...
print_structure (link);
...
}

Could anybody help me spot the problem?

/* BEGIN new.c */

#include <stdio.h>

#define MAX_GRAPH 3

typedef struct edge {
long delay;
long bandw;
} edge;

size_t nodes = MAX_GRAPH;

void print_structure (edge (*graph)[MAX_GRAPH]);

int main(void)
{
edge link[MAX_GRAPH][MAX_GRAPH] = {
1,2,3,4,5,6,7,8 ,9,10,11,12,13, 14,15,16
};

print_structure (link);
return 0;
}

void print_structure (edge (*graph)[MAX_GRAPH])
{
size_t i, j;

for(i = 0; i < nodes; i++){
for(j=0;j < nodes; j++){
printf("[%d][%d].bandw = %ld\t", i, j, graph[i][j].bandw);
printf("[%d][%d].delay = %ld\n", i, j, graph[i][j].delay);
}
}
}

/* END new.c */
--
pete

[estantep]

Ark and Pete, Thank you _very_ much.

You guys are the best.
pete wrote:

es******@gmail. com wrote:

Hello,

I am having some trouble trying to pass a pointer to an structure
array (as function argument), when executing I get seg faults.

The best I could get out from googling was:

#define MAX_GRAPH 256

typedef struct edge{
long delay;
long bandw;
} edge;

edge link[MAX_GRAPH][MAX_GRAPH];

int print_structure (edge *graph[MAX_GRAPH][MAX_GRAPH]){
int i, j;
for(i=0;i<nodes ;i++){
for(j=0;j<nodes ;j++){
printf("[%d][%d].bandw = %d\t\t", i, j, graph[i][j]->bandw); //
SEG FAULT!
printf("[%d][%d].delay = %d\n", i, j, graph[i][j]->delay);
}
}
return 0;
}

int main(int argc, char* argv[]){

...
print_structure (link);
...
}

Could anybody help me spot the problem?

/* BEGIN new.c */

#include <stdio.h>

#define MAX_GRAPH 3

typedef struct edge {
long delay;
long bandw;
} edge;

size_t nodes = MAX_GRAPH;

void print_structure (edge (*graph)[MAX_GRAPH]);

int main(void)
{
edge link[MAX_GRAPH][MAX_GRAPH] = {
1,2,3,4,5,6,7,8 ,9,10,11,12,13, 14,15,16
};

print_structure (link);
return 0;
}

void print_structure (edge (*graph)[MAX_GRAPH])
{
size_t i, j;

for(i = 0; i < nodes; i++){
for(j=0;j < nodes; j++){
printf("[%d][%d].bandw = %ld\t", i, j, graph[i][j].bandw);
printf("[%d][%d].delay = %ld\n", i, j, graph[i][j].delay);
}
}
}

/* END new.c */
--
pete

[Ben Bacarisse]

es******@gmail. com writes:

Hello,

I am having some trouble trying to pass a pointer to an structure
array (as function argument), when executing I get seg faults.

The best I could get out from googling was:

#define MAX_GRAPH 256

typedef struct edge{
long delay;
long bandw;
} edge;

edge link[MAX_GRAPH][MAX_GRAPH];

int print_structure (edge *graph[MAX_GRAPH][MAX_GRAPH]){

Loose the initial *. You end up with:

edge graph[MAX_GRAPH][MAX_GRAPH]

is fine, but the first size is redundant -- because a pointer to the
array will be passed, C only insists that you say exactly what each
element of this array is like, not how many there are. This one can
also (and equivalently) write:

edge graph[][MAX_GRAPH]
edge (*graph)[MAX_GRAPH]

int i, j;
for(i=0;i<nodes ;i++){
for(j=0;j<nodes ;j++){
printf("[%d][%d].bandw = %d\t\t", i, j, graph[i][j]->bandw); //
SEG FAULT!
printf("[%d][%d].delay = %d\n", i, j, graph[i][j]->delay);

Since the array contains structures, you need to use . to access the
elements. Note, also, that you should use %ld to print 'long int's.

}
}
return 0;
}
int main(int argc, char* argv[]){

...
print_structure (link);
...
}

--
Ben.

[Barry Schwarz]

On Sun, 19 Aug 2007 22:52:12 -0000, es******@gmail. com wrote:

>Hello,

I am having some trouble trying to pass a pointer to an structure
array (as function argument), when executing I get seg faults.

Why do you execute code (the only way to get a seg fault) when the
compiler has already told you that the code is incorrect? If you did
not receive a diagnostic for the constraint violation in your call to
print_structure , you need to up the warning level of your compiler.

>
The best I could get out from googling was:

#define MAX_GRAPH 256

typedef struct edge{
long delay;
long bandw;
} edge;

edge link[MAX_GRAPH][MAX_GRAPH];

link is an array of struct.

>
int print_structure (edge *graph[MAX_GRAPH][MAX_GRAPH]){

This function is expecting an array of pointer to struct. Due the
fact that an array expression in this context is converted to a
pointer to the first element, the actual type the function is
expecting is
edge (*)(*[MAX_GRAPH])

int i, j;
for(i=0;i<nodes ;i++){

We won't ask about nodes.

for(j=0;j<nodes ;j++){
printf("[%d][%d].bandw = %d\t\t", i, j, graph[i][j]->bandw); //
SEG FAULT!
printf("[%d][%d].delay = %d\n", i, j, graph[i][j]->delay);
}
}
return 0;
}
int main(int argc, char* argv[]){

...
print_structure (link);

Here you pass the array. Since the same conversion is performed, the
actual type passed is
edge (*)[MAX_GRAPH]

Notice that these are not the same type. There is also no implicit
conversion between these two types. Hence the required diagnostic.

If you delete the asterisk from the parameter in the function
definition, your code will be consistent. Then you can start to worry
about correcting the undetected coding errors, such as using %d when
you actually pass printf a long instead of an int.
Remove del for email

[Chris Torek]

>On Sun, 19 Aug 2007 22:52:12 -0000, es******@gmail. com wrote:
[given: a typedef-alias named "edge", a #define constant for
MAX_GRAPH, and]

>>int print_structure (edge *graph[MAX_GRAPH][MAX_GRAPH]){

In article <ak************ *************** *****@4ax.com>
Barry Schwarz <sc******@doezl .netwrote:

>This function is expecting an array of pointer to struct.

Well, the type of the argument named "graph" is -- before the
adjustment you describe in a moment -- "array MAX_GRAPH of array
MAX_GRAPH of pointer to what-edge-is-short-for". So, array of
arrays, each element of the nested array being a pointer to struct
(since edge is short for a struct type).

>Due the fact that an array expression in this context is converted
to a pointer to the first element, the actual type the function is
expecting is
edge (*)(*[MAX_GRAPH])

Right -- a formal parameter whose type *appears* to be "array N of
T" (for some integer N, or even an omitted integer, and any valid
type T) really gets declared as having type "pointer to T", replacing
the first (and only the first!) "array of" part of the expanded
English version with "pointer to" -- except that the C spelling of
the type "pointer to array MAX_GRAPH of pointer to
whatever-edge-is-short-for" is actually:

edge *(*)[MAX_GRAPH]

The parentheses "look weird" because we lack the identifier that
would go in there. If this were an actual declaration instead of
just a type-name, we would have:

edge *(*ptr)[MAX_GRAPH];

Here, the need for the parentheses is clearer (if not exactly
"clear"!) since we need to bind the inner (second) "*" to "ptr",
then bind the "[MAX_GRAPH]" to that, and then bind the outer (first)
"*" to that, and finally bind the typedef-alias "edge" to that.
Without parentheses, the "[MAX_GRAPH]" would bind to "ptr" first,
then the second "*" would bind to that, and so on.

To turn a C declaration into a type-name, one simply removes the
identifier that was being declared. In this case, it results in
parentheses around the second "*".
--
In-Real-Life: Chris Torek, Wind River Systems
Salt Lake City, UT, USA (40°39.22'N, 111°50.29'W) [phone]
email: forget about it http://web.torek.net/torek/index.html
Reading email is like searching for food in the garbage, thanks to spammers.

[¬a\\/b]

On 24 Aug 2007 06:43:22 GMT, Chris Torek wrote:

>[given: a typedef-alias named "edge", a #define constant for
MAX_GRAPH, and]

>>>int print_structure (edge *graph[MAX_GRAPH][MAX_GRAPH]){

In article <ak************ *************** *****@4ax.com>
Barry Schwarz wrote:

>>This function is expecting an array of pointer to struct.

Well, the type of the argument named "graph" is -- before the
adjustment you describe in a moment -- "array MAX_GRAPH of array
MAX_GRAPH of pointer to what-edge-is-short-for". So, array of
arrays, each element of the nested array being a pointer to struct
(since edge is short for a struct type).

>>Due the fact that an array expression in this context is converted
to a pointer to the first element, the actual type the function is
expecting is
edge (*)(*[MAX_GRAPH])

Right -- a formal parameter whose type *appears* to be "array N of
T" (for some integer N, or even an omitted integer, and any valid
type T) really gets declared as having type "pointer to T", replacing
the first (and only the first!) "array of" part of the expanded
English version with "pointer to" -- except that the C spelling of
the type "pointer to array MAX_GRAPH of pointer to
whatever-edge-is-short-for" is actually:

edge *(*)[MAX_GRAPH]

The parentheses "look weird" because we lack the identifier that
would go in there. If this were an actual declaration instead of
just a type-name, we would have:

edge *(*ptr)[MAX_GRAPH];

Here, the need for the parentheses is clearer (if not exactly
"clear"!) since we need to bind the inner (second) "*" to "ptr",
then bind the "[MAX_GRAPH]" to that, and then bind the outer (first)
"*" to that, and finally bind the typedef-alias "edge" to that.
Without parentheses, the "[MAX_GRAPH]" would bind to "ptr" first,
then the second "*" would bind to that, and so on.

To turn a C declaration into a type-name, one simply removes the
identifier that was being declared. In this case, it results in
parentheses around the second "*".

possibly
i'm not enough smart
possibly
all you game with nothing (i think all is easy but there are people
that complicates languages)
with an easy language is possible to write something that in a
difficult language can not to be written

i hope i offend nobody

[Mark Bluemel]

¬a\/b wrote:

On 24 Aug 2007 06:43:22 GMT, Chris Torek wrote:

<snip>

>
possibly
i'm not enough smart
possibly
all you game with nothing (i think all is easy but there are people
that complicates languages)
with an easy language is possible to write something that in a
difficult language can not to be written

i hope i offend nobody

I'd have to be able to understand what you've written before I could be
offended by it...

[santosh]

¬a\/b wrote:

On 24 Aug 2007 06:43:22 GMT, Chris Torek wrote:

[yet another superb but intricate explanation]

possibly
i'm not enough smart
possibly
all you game with nothing (i think all is easy but there are people
that complicates languages)
with an easy language is possible to write something that in a
difficult language can not to be written

i hope i offend nobody

Check out Lisp or Forth.