char *query[]

[gert]

Why does query[1] = www ?

int
main(void)
{
char *user="www";
char *password="";
char *database="www" ;
char *query[]={"SHOW DATABASES;"};
db(user,passwor d,database,quer y);
}

(gdb) next
12 char *query[]={"SHOW DATABASES;"};
(gdb) next
13 db(user,passwor d,database,quer y);
(gdb) print query
$5 = {0x400e25 "SHOW DATABASES;"}
(gdb) print query[0]
$6 = 0x400e25 "SHOW DATABASES;"
(gdb) print query[1]
$7 = 0x400e20 "www"
(gdb) print query[2]
$8 = 0x400e24 ""
(gdb) print query[3]
$9 = 0x400e20 "www"
(gdb) print query[4]
$10 = 0x0
(gdb)

source
----------
http://dfo.svn.sourceforge.net/viewv...74&view=markup

[Barry Schwarz]

On Sun, 15 Jul 2007 16:57:56 -0000, gert <ge**********@g mail.com>
wrote:

>On Jul 15, 6:47 pm, gert <gert.cuyk...@g mail.comwrote:

>There goes my carefully thought out NASA for loop :(

for(q=0;s=quer y[q];q++)

Guess the only solution would be using a max value then ?

o wait a minute what about

char **query = {"SHOW DATABASES;", 0x0 };

Did you try this? Did you not get a compiler diagnostic complaining
about too many initializers?

>

>(gdb) print query[4]
$10 = 0x0

How can i force a 0x0 boundary ?

First tell us what a 0x0 boundary is. Do you mean where the address
is always a multiple of 0x10? If so, there is no way to do so
portably.
Remove del for email

[crox]

On Jul 15, 9:20 pm, j...@toerring.d e (Jens Thoms Toerring) wrote:

gert <gert.cuyk...@g mail.comwrote:

On Jul 15, 6:47 pm, gert <gert.cuyk...@g mail.comwrote:

There goes my carefully thought out NASA for loop :(

for(q=0;s=query[q];q++)

Guess the only solution would be using a max value then ?

o wait a minute what about
char **query = {"SHOW DATABASES;", 0x0 };

You should use NULL instead of 0x0 - NULL is null pointer
while 0x0 is an integer constant (and the representation
of a null pointer isn't necessarily all bits 0 as in 0x0).

Now you can use your loop

for (q=0;s=query[q];q++ )

since s will be set to NULL for q==1 amd thus the loop will
end without accessing a non-existing array element.

(gdb) print query[4]
$10 = 0x0

How can i force a 0x0 boundary ?

I don't know what you mean with "0x0 boundary", but you
simply aren't allowed to ty to access elements past the
end of the array and you must find a way to avoid that,
like the one you already came up with, i.e. by having a
NULL pointer as the last element that you can test for.

Regards, Jens
--
\ Jens Thoms Toerring ___ j...@toerring.d e
\______________ ____________ http://toerring.de

Why not to use?
char *elem;
int i;
....
for(i=0; i < sizeof(query); i++) {
do_something_wi th(query[i]);
}
It is more straightforward and simple solution, I think.

crox

[Ben Bacarisse]

crox <cr*****@gmail. comwrites:

On Jul 15, 9:20 pm, j...@toerring.d e (Jens Thoms Toerring) wrote:

>gert <gert.cuyk...@g mail.comwrote:

On Jul 15, 6:47 pm, gert <gert.cuyk...@g mail.comwrote:
There goes my carefully thought out NASA for loop :(

for(q=0;s=query[q];q++)

Guess the only solution would be using a max value then ?
o wait a minute what about
char **query = {"SHOW DATABASES;", 0x0 };

<snip>

>--
\ Jens Thoms Toerring ___ j...@toerring.d e
\______________ ____________ http://toerring.de

Don't quote sigs.

Why not to use?
char *elem;
int i;
...
for(i=0; i < sizeof(query); i++) {
do_something_wi th(query[i]);
}
It is more straightforward and simple solution, I think.

Did you mean 'i < sizeof(query)/sizeof(*query)' perhaps? I am not sure
because of the mysterious 'char *elem;' declaration.

To the OP: if you go this route, take the terminating NULL (0x0) out
of the array and you must, of course, declare 'query' as an array:

char *query[] = { "one", "two" };

--
Ben.

[crox]

On Jul 16, 3:16 pm, Ben Bacarisse <ben.use...@bsb .me.ukwrote:

crox <craz...@gmail. comwrites:

On Jul 15, 9:20 pm, j...@toerring.d e (Jens Thoms Toerring) wrote:

gert <gert.cuyk...@g mail.comwrote:
On Jul 15, 6:47 pm, gert <gert.cuyk...@g mail.comwrote:
There goes my carefully thought out NASA for loop :(

for(q=0;s=query[q];q++)

Guess the only solution would be using a max value then ?
o wait a minute what about
char **query = {"SHOW DATABASES;", 0x0 };

<snip>

--
\ Jens Thoms Toerring ___ j...@toerring.d e
\______________ ____________ http://toerring.de

Don't quote sigs.

Why not to use?
char *elem;
int i;
...
for(i=0; i < sizeof(query); i++) {
do_something_wi th(query[i]);
}
It is more straightforward and simple solution, I think.

Did you mean 'i < sizeof(query)/sizeof(*query)' perhaps? I am not sure
because of the mysterious 'char *elem;' declaration.

To the OP: if you go this route, take the terminating NULL (0x0) out
of the array and you must, of course, declare 'query' as an array:

char *query[] = { "one", "two" };

--
Ben.

Oops, sorry I mean:
char *query[] = {"Do 1", "Do 2"};
int i;
...
for(i=0; i < sizeof(query); i++) {
do_something_wi th(query[i]);
}

[santosh]

crox wrote:

On Jul 16, 3:16 pm, Ben Bacarisse <ben.use...@bsb .me.ukwrote:

crox <craz...@gmail. comwrites:

On Jul 15, 9:20 pm, j...@toerring.d e (Jens Thoms Toerring) wrote:
>gert <gert.cuyk...@g mail.comwrote:
On Jul 15, 6:47 pm, gert <gert.cuyk...@g mail.comwrote:
There goes my carefully thought out NASA for loop :(

for(q=0;s=query[q];q++)

Guess the only solution would be using a max value then ?
o wait a minute what about
char **query = {"SHOW DATABASES;", 0x0 };

<snip>

>--
> \ Jens Thoms Toerring ___ j...@toerring.d e
> \______________ ____________ http://toerring.de

Don't quote sigs.

Why not to use?
char *elem;
int i;
...
for(i=0; i < sizeof(query); i++) {
do_something_wi th(query[i]);
}
It is more straightforward and simple solution, I think.

Did you mean 'i < sizeof(query)/sizeof(*query)' perhaps? I am not sure
because of the mysterious 'char *elem;' declaration.

To the OP: if you go this route, take the terminating NULL (0x0) out
of the array and you must, of course, declare 'query' as an array:

char *query[] = { "one", "two" };

--
Ben.

When will you do us the favour of not quoting sigs?

Oops, sorry I mean:
char *query[] = {"Do 1", "Do 2"};
int i;
...
for(i=0; i < sizeof(query); i++) {
do_something_wi th(query[i]);
}

This is wrong. sizeof(query) will return the size, in bytes of the
array named query. You want the number of elements in the array. For
that, you should do:

sizeof query / sizeof query[0];

This will yield two.