I have a class Feature defined, which is a kind of Vocab:
template <class T, unsigned I>
class Vocab : boost::totally_ ordered<Vocab<T ,I {
public:
Vocab();
Vocab(const T& t);
template<typena me VVocab(V v, bool dummy);
....
};
typedef Vocab<string, 0Feature;
Then, I try to specialize (define?) the templated constructor:
template<>
inline Feature::Vocab( pair<parser::id _ty, stringp, bool dummy) {
...
}
This code compiles under g++ 3.4, but under g++ 4 I get the following
errors:
src/specialize-bdt.H:37: error: template-id 'Vocab<>' for
'bdt::Vocab<std ::string, 0u>::Vocab(std: :pair<parser::i d_ty,
std::string>, bool)' does not match any template declaration
src/specialize-bdt.H:37: error: invalid function declaration
What is the problem here?
Thanks,
Joseph 2 4508
Joseph Turian wrote:
I have a class Feature defined, which is a kind of Vocab:
template <class T, unsigned I>
class Vocab : boost::totally_ ordered<Vocab<T ,I {
public:
Vocab();
Vocab(const T& t);
template<typena me VVocab(V v, bool dummy);
....
};
typedef Vocab<string, 0Feature;
Then, I try to specialize (define?) the templated constructor:
template<>
inline Feature::Vocab( pair<parser::id _ty, stringp, bool dummy) {
...
}
This code compiles under g++ 3.4, but under g++ 4 I get the following
errors:
src/specialize-bdt.H:37: error: template-id 'Vocab<>' for
'bdt::Vocab<std ::string, 0u>::Vocab(std: :pair<parser::i d_ty,
std::string>, bool)' does not match any template declaration
src/specialize-bdt.H:37: error: invalid function declaration
What is the problem here?
I don't think you can use 'Feature' to write the specialisation (but
I can be wrong). Have you tried
template<>
template<>
inline Vocab<string,0> ::Vocab(pair<pa r....
?
V
--
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I do not respond to top-posted replies, please don't ask
I don't think you can use 'Feature' to write the specialisation (but
I can be wrong). Have you tried
template<>
template<>
inline Vocab<string,0> ::Vocab(pair<pa r....
Thanks for the advice. At least according to gcc, I can use Feature:
template<>
template<>
inline Feature::Vocab( pair<par....
The second "template<> " did the trick, so thanks! :)
Best,
Joseph This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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