gettin d average!!

[1051109210]

write a program that will accept 2
integer numbers from the user and
then display out
all the integer
numbers in between
those two integers
excluding the two
numbers, then
display the avg
among the output
displayed.

#include<iostream>
using namespace std;
 
int main()
{
double one,two,i,j,sum=0,a,b;//declaring variables
 
 
cout<< "first value = ";//ask for first num
cin>>one;               //first input
cout<<"second value = ";//ask for second num
cin>>two;               //second input
 
cout<<'\n';             //skip a line
 
       if(two>one){
            for(i=one;i<=two;i++)
            cout<< i <<endl;
                     for (int i=1; i<=two; i++)
                     sum = sum + i;
                     cout<<sum/i<<endl;
       }else{
            for(j=two;j<=one;j++)
            cout<< j <<endl;
                  }
 
 
 
    system("pause");
    return 0;
}

after this im stuck...i cant get the average part to work out rite! anyone able to help me out i can get it to sum up but i cant get it to divide so i'll get d average

[arne]

write a program that will accept 2
integer numbers from the user and
then display out
all the integer
numbers in between
those two integers
excluding the two
numbers, then
display the avg
among the output
displayed.

#include<iostre am>
using namespace std;

int main()
{
double one,two,i,j,sum =0,a,b;//declaring variables


cout<< "first value = ";//ask for first num
cin>>one; //first input
cout<<"second value = ";//ask for second num
cin>>two; //second input

cout<<'\n'; //skip a line

if(two>one){
for(i=one;i<=tw o;i++)
cout<< i <<endl;
for (int i=1; i<=two; i++)
sum = sum + i;
cout<<sum/i<<endl;
}else{
for(j=two;j<=on e;j++)
cout<< j <<endl;
}



system("pause") ;
return 0;
}



after this im stuck...i cant get the average part to work out rite! anyone able to help me out i can get it to sum up but i cant get it to divide so i'll get d average

You were almost there. Try this

    if (one == two || one+1 == two || one == two+1 ) {
 
        /* nothing to do */
        return 0;
    }
 
    if (two < one) {
 
        /* make sure one < two */
        double tmp;
        tmp = one;
        one = two;
        two = tmp;
    }
 
    for (i=one+1; i<two; i++) {
 
        cout << i << endl;
        sum = sum + i;
    }
 
    cout << sum/(two-one-1) << endl;
 

Note that I changed the conditions in the loop and the divisor for the average.

[1051109210]

wo thnks alot! really helped...

[melodyii]

write a program that will accept 2
integer numbers from the user and
then display out
all the integer
numbers in between
those two integers
excluding the two
numbers, then
display the avg
among the output
displayed.

#include<iostre am>
using namespace std;

int main()
{
double one,two,i,j,sum =0,a,b;//declaring variables


cout<< "first value = ";//ask for first num
cin>>one; //first input
cout<<"second value = ";//ask for second num
cin>>two; //second input

cout<<'\n'; //skip a line

if(two>one){
for(i=one;i<=tw o;i++)
cout<< i <<endl;
for (int i=1; i<=two; i++)
sum = sum + i;
cout<<sum/i<<endl;
}else{
for(j=two;j<=on e;j++)
cout<< j <<endl;
}



system("pause") ;
return 0;
}



after this im stuck...i cant get the average part to work out rite! anyone able to help me out i can get it to sum up but i cant get it to divide so i'll get d average

owH! U donT use Printf and scanf?

[Ganon11]

printf and scanf are functions used mainly in C, but have been replaced by cout and cin in C++. You can still use scanf/printf if you include the header file <cstdio>