Hi
What is the correct way to delete an element from STL list while
iterating through the list
list<A*> _ls;
A * a;
list<A*>::itera tor si1;
for (si1=_ls.begin( ); si1!=_ls.end(); ++si1) {
if ( (*si1)->check() ) {
a =(*si);
_ls.erase(si1);
/* Now this function will point pint si1 to next element. (no
invalidate) Now how to still continue with for loop which will be a
problem now ??? ..
*/
delete a;
}
} 13  20482 
"Paras" <pa******@netsc ape.net> wrote in message
news:3F******** ****@netscape.n et...
Hi
What is the correct way to delete an element from STL list while
iterating through the list
list<A*> _ls;
A * a;
list<A*>::itera tor si1;
for (si1=_ls.begin( ); si1!=_ls.end(); ++si1) {
if ( (*si1)->check() ) {
a =(*si);
_ls.erase(si1);
/* Now this function will point pint si1 to next element. (no
invalidate) Now how to still continue with for loop which will be a
problem now ??? ..
*/
delete a;
}
}
list<A*> _ls;
A* a;
list<A*>::itera tor si1 = _ls.begin();
while (si1 != _ls.end())
{
if ((*si1)->check())
{
a = *si1;
// si1 points to the next element after erase()
si1 = _ls.erase(si1);
delete a;
}
else
++si1;
}
--
ES Kim
Hello,
erase returns a iterator to first element remaining beyond any elements
removed.so use this
I like *while* so i have changed it to while sorry..;-)
Hope this helps.
//Code
list<A*> _ls;
A * a;
list<A*>::itera tor si1 = _ls.begin();
while(si1 !=_ls.end()) {
if ( (*si1)->check() ) {
a =(*si);
si1 = _ls.erase(si1);
delete a;
}
else
{
si1++;
}
}
"Paras" <pa******@netsc ape.net> wrote in message
news:3F******** ****@netscape.n et...
Hi
What is the correct way to delete an element from STL list while
iterating through the list
list<A*> _ls;
A * a;
list<A*>::itera tor si1;
for (si1=_ls.begin( ); si1!=_ls.end(); ++si1) {
if ( (*si1)->check() ) {
a =(*si);
_ls.erase(si1);
/* Now this function will point pint si1 to next element. (no
invalidate) Now how to still continue with for loop which will be a
problem now ??? ..
*/
delete a;
}
}
"ES Kim" <es***@svd.co.k r> wrote in message
news:bh******** **@news1.kornet .net... "Paras" <pa******@netsc ape.net> wrote in message
news:3F******** ****@netscape.n et...
Hi
What is the correct way to delete an element from STL list while
iterating through the list
[snip]
list<A*> _ls;
A* a;
list<A*>::itera tor si1 = _ls.begin();
while (si1 != _ls.end())
{
if ((*si1)->check())
{
a = *si1;
// si1 points to the next element after erase()
si1 = _ls.erase(si1);
delete a;
No good reason for the a varaible
delete *si1;
si1 = _ls.erase(si1);
}
else
++si1;
}
--
ES Kim
john
"Naren" <na************ *@in.bosch.com> wrote in message
news:bh******** **@ns2.fe.inter net.bosch.com.. . Hello,
erase returns a iterator to first element remaining beyond any elements
removed.so use this
I like *while* so i have changed it to while sorry..;-)
Hope this helps.
//Code
[SNIP]
else
{
si1++;
In this case I'd recommend to use ++si1; instead because it might be more
efficient. Anyway there's nothing to lose if you use prefix instead of
postfix notation in a case like this.
}
}
Chris
Paras <pa******@netsc ape.net> wrote in message news:<3F******* *****@netscape. net>... Hi
What is the correct way to delete an element from STL list while
iterating through the list
list<A*> _ls;
A * a;
list<A*>::itera tor si1;
for (si1=_ls.begin( ); si1!=_ls.end(); ++si1) {
if ( (*si1)->check() ) {
a =(*si);
_ls.erase(si1);
/* Now this function will point pint si1 to next element. (no
invalidate) Now how to still continue with for loop which will be a
problem now ??? ..
*/
delete a;
}
}
Other people appear to have answered your question, but just to point
out:
Names beginning with an underscore are reserved for the implementation
in the global namespace so, depending on context, _ls might not be the
best name for your list.
GJD
Gavin Deane wrote: Names beginning with an underscore are reserved for the implementation
in the global namespace
I thought this only applied if that undersore was followed by an
uppercase letter.
"Rob Williscroft" <rt*@freenet.RE MOVE.co.uk> wrote in message
If I remember/understand correctly, those names and those with two
underscores are reserved anywhere, i.e. so the implementor can use
them as macro's.
And also to set off the decorations from the rest of the identifier (the
double-underscore prohibition isn't just for leading undersdcores but
anywhere in the identifier).
Identifiers with a single leading underscore are reserved only in
the global namespace.
NO. Indentifiers with leading underscore and a captial letter are not
permitted anywhere. If you look at a lot of the template library you'll
see many implementations use these symbols as their template variables,
etc...to keep things from colliding with possible user macro definitions.
It is _ followed by non-uppercase letters that is reserved ONLY in the
global namespace. These are typically used for certain implementation
defined global functions etc...
llewelly wrote in news:86******** ****@Zorthluthi k.local.bar: If I remember/understand correctly, those names and those with two
underscores are reserved anywhere, i.e. so the implementor can use
them as macro's.
[snip]
Two *consecutive* underscores; i.e. this_is_okay this__is_not
Yes, It's what I meant but not what I wrote, Thanks.
Rob.
-- http://www.victim-prime.dsl.pipex.com/
Rob Williscroft <rt*@freenet.RE MOVE.co.uk> wrote in message news:<Xn******* *************** ************@19 5.129.110.201>. .. llewelly wrote in news:86******** ****@Zorthluthi k.local.bar:
If I remember/understand correctly, those names and those with two
underscores are reserved anywhere, i.e. so the implementor can use
them as macro's.
[snip]
Two *consecutive* underscores; i.e. this_is_okay this__is_not
Yes, It's what I meant but not what I wrote, Thanks.
Rob.
I guess the level of uncertainty here lends weight to the argument
that it's simpler just to avoid leading underscores altogether (which
is my preference anyway). I checked the standard before my original
post in this thread so I'm fairly sure it was right, but the fact that
I felt I needed to supports that argument.
GJD This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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