Hi,
I want to create a static array whose size is also a const
member of the class. Something like:
// A.h
class A {
private:
static int size = 0;
static int array[size];
};
Then I need to define the static array in A.cpp like:
int A::array[A::size];
However, the compiler complains that A::size is a private
and cannot be accessed. So how can I define such a static
array without making the size of the array public ?
Thanks,
Rahul 3 35283
Rahul Joshi wrote: ... I want to create a static array whose size is also a const member of the class. Something like:
// A.h class A { private: static int size = 0; static int array[size]; };
Then I need to define the static array in A.cpp like:
int A::array[A::size];
However, the compiler complains that A::size is a private and cannot be accessed. So how can I define such a static array without making the size of the array public ? ...
Aside from missing 'const' specifier and array size being zero, I don't
see any problems with this code. (Please, always post _real_ code, i.e.
the code you are actually trying to compile.)
The error message is most likely caused by a bug in your compiler.
According to 11/5 access control is not supposed to restrict access to
'A::size' in the above member definition.
--
Best regards,
Andrey Tarasevich
Brainbench C and C++ Programming MVP
i think you just make a mistake when you declare
static int array[size] ;
because std c++ doesn't support "dynamic" declare , you know size is not a
const number, so this will generate a mistake. and i compile it in dev-c++
4.9.8.0 with winme,
it just appear "4 D:\source code\stl_c++\st atictest.h
size of member `array' is not constant"
so if you want to achive this ,i think the best way is to use stl: vector.
"Rahul Joshi" <ru*****@studen ts.uiuc.edu>
??????:Pi****** *************** *************** *@ux7.cso.uiuc. edu... Hi,
I want to create a static array whose size is also a const member of the class. Something like:
// A.h class A { private: static int size = 0; static int array[size]; };
Then I need to define the static array in A.cpp like:
int A::array[A::size];
However, the compiler complains that A::size is a private and cannot be accessed. So how can I define such a static array without making the size of the array public ?
Thanks, Rahul
On Thu, 17 Jul 2003, Andrey Tarasevich wrote: Rahul Joshi wrote: ... I want to create a static array whose size is also a const member of the class. Something like:
// A.h class A { private: static int size = 0; static int array[size]; };
Then I need to define the static array in A.cpp like:
int A::array[A::size];
However, the compiler complains that A::size is a private and cannot be accessed. So how can I define such a static array without making the size of the array public ? ...
Aside from missing 'const' specifier and array size being zero, I don't see any problems with this code. (Please, always post _real_ code, i.e. the code you are actually trying to compile.)
The error message is most likely caused by a bug in your compiler. According to 11/5 access control is not supposed to restrict access to 'A::size' in the above member definition.
-- Best regards, Andrey Tarasevich Brainbench C and C++ Programming MVP
Sorry. That was some code I made up. I was trying to define a static array
of pointers-to-member functions of the class, and the size of this array
is a static const int. Apparently, my syntax was wrong. As suggested in
C++ FAQ, I used a typedef for the pointer-to-member type, and it compiled
correctly. Thanks.
Rahul This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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