Partial specialisation of method taking parameterized parameter

[=?iso-8859-1?q?Erik_Wikstr=F6m?=]

I'd like to create a partial specialization of a member-method of a
parameterized class which takes a parameterized argument, but I'm not
sure if it's possible or, if possible, how. The following code
demonstrates what I'd like to to:

#include <iostream>

template<class T>
struct BarA
{
void bar() { std::cout << "BarA\n"; }
};

template<class T>
struct BarB
{
void bar() { std::cout << "BarB\n"; }
};

template<class T>
struct Test
{
template<templa te<class U = Tclass V>
void foo(V<T>& f);
};

template<class T>
template<templa te<classclass V>
void Test<T>::foo(V< T>& f)
{
f.bar();

}

/* A partial specialization that prepends the output of f.bar() with
"BarB: "
template<class T>
template<>
void Test<T>::foo(Ba rB<Tf)
{
std::cout "BarB: ";
f.bar();
}
*/

int main()
{
BarA<inta;
BarB<intb;

Test<intt;
t.foo(a);
t.foo(b);
}

This should, print:
BarA
BarB: BarB

Any help appreciated.

--
Erik Wikström

[dasjotre]

Erik Wikström wrote:

template<class T>
struct Test
{
template<templa te<class U = Tclass V>
void foo(V<T>& f);

void foo(BarB<T&f);

};

template<class T>
template<templa te<classclass V>
void Test<T>::foo(V< T>& f)
{
f.bar();

}

template<class T>
void Test<T>::foo(Ba rB<T& f)
{
std::cout << "BarB: ";
f.bar();
}

[=?iso-8859-1?q?Erik_Wikstr=F6m?=]

On Dec 20, 2:54 pm, "dasjotre" <dasjo...@googl email.comwrote:

Erik Wikström wrote:

template<class T>
struct Test
{
template<templa te<class U = Tclass V>
void foo(V<T>& f); void foo(BarB<T&f);

};

template<class T>
template<templa te<classclass V>
void Test<T>::foo(V< T>& f)
{
f.bar();

}template<class T>

void Test<T>::foo(Ba rB<T& f)
{
std::cout << "BarB: ";
f.bar();
}

Yes, of course. Thanks.

--
Erik Wikström

[Victor Bazarov]

Erik Wikström wrote:

I'd like to create a partial specialization of a member-method [..]

You can stop right there. C++ does not allow partial specialisations
of function templates. Another mistake: you cannot specialise any
member without first specialising the class template.

The specification you gave in the form of your [non-compiling] code
is a bit unclear. Are you trying to make your 'foo' member have
a different behaviour if the template for which it's instantiated is
'BarB' (versus any other)? It is very likely you need a helper class
template for that. You can then specialise your helper template:

template<class Tstruct TestHelper {
static void help() {} // do nothing for all
};

template<class Tsturct TestHelper<BarB <T {
static void help() { std::cout << "BarB: "; }
};

template<class Tstruct Test {
template<templa te<classclass Bvoid foo(B<Tf) {
TestHelper<B<T: :help(); ///////////////////// some help
f.bar();
}
};

V
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