Char * to LPWSTR

[MattWilson.6185]

Hello!

I am trying to convert a char * to a LPWSTR, and I am going absolutly
mad! I can't find anything besides typle L"string" Unfortunetaly I
can't use that...

basicaly the setup is

callbackFromAno therFunctionWhi chMustBeOfChar( char* helpMe) {
//...
foo(some LPWSTR conversion);
}

this is the closest I have come to acomplishing this

char* convertMe = new char[sizeof(material s[i].pTextureFilena me)];
strcpy(convertM e,materials[i].pTextureFilena me);
wchar_t fileNameBuff[1];
int buffSize =
MultiByteToWide Char(CP_ACP,0,c onvertMe,strlen (convertMe),fil eNameBuff,0);
LPWSTR gah = (LPWSTR)new wchar_t[buffSize];
MultiByteToWide Char(CP_ACP,0,c onvertMe,strlen (convertMe),gah ,buffSize);

it converts all of the characters but I get a bunch of junk at the end
and I can't open the file.

Thanks :)

[Martijn van Buul]

* Ma************* @gmail.com:

callbackFromAno therFunctionWhi chMustBeOfChar( char* helpMe) {
//...
foo(some LPWSTR conversion);
}

Terribly off-topic here as it's not about C++, but about stupid MFC/ATL, but
you might want to peek at i

http://msdn2.microsoft.com/en-us/lib...a3(VS.80).aspx

--
Martijn van Buul - pi**@dohd.org

[Ron Natalie]

Ma************* @gmail.com wrote:

Hello!

I am trying to convert a char * to a LPWSTR, and I am going absolutly
mad! I can't find anything besides typle L"string" Unfortunetaly I
can't use that...

L"string" is an array of wchar_t characters.
The topical question is how to change an array of
char to an array of wchar_t.

char narrowarray[] = "Mairzy doats and dozy doats.";
wchar_t widearray[100]
mbstowcs(widear ray, narrowarray, 100);

LPSTR is a Microsoft abomination

[MattWilson.6185]

L"string" is an array of wchar_t characters.

The topical question is how to change an array of
char to an array of wchar_t.

char narrowarray[] = "Mairzy doats and dozy doats.";
wchar_t widearray[100]
mbstowcs(widear ray, narrowarray, 100);

LPSTR is a Microsoft abomination

Here Here! Thank you so much for the answer! I now have a curiosity
question if any are willing to indulge, to solve the problem i had
earlier I used

strcpy(convertM e,materials[i].pTextureFilena me);
wchar_t fileNameBuff[1];
int buffSize
=MultiByteToWid eChar(CP_ACP,0, convertMe,strle n(convertMe),fi leNameBuff,0);
LPWSTR gah = (LPWSTR)new wchar_t[buffSize];
MultiByteToWide Char(CP_ACP,0,c onvertMe,strlen (convertMe),gah ,buffSize);
/*LOOK HERE!!*/
wstring final;
for(int i = 0; i < sizeof(convertM e)*2+1;i++) {
final.push_back (gah[i]);

Can anyone tell me, why did I have to use a size of 2 + 1? It makes NO
sence at all to me, I mean I understand a wchar is twice as many bytes,
however in traversing the array does it access each part per byte
(char)? And if so then how does push_back understand it's getting char
and not wchar? Even when it's clearly being fed a wchar... I should
be able to say final.push_back (L"w"); not final.push_back "(L"w");
final.push_back (0); or whatever it be

thanks ;)

Matt

[Dag Viken]

<Ma************ *@gmail.comwrot e in message
news:11******** **************@ h54g2000cwb.goo glegroups.com.. .

Hello!

I am trying to convert a char * to a LPWSTR, and I am going absolutly
mad! I can't find anything besides typle L"string" Unfortunetaly I
can't use that...

basicaly the setup is

callbackFromAno therFunctionWhi chMustBeOfChar( char* helpMe) {
//...
foo(some LPWSTR conversion);
}

Matt,
You should probably post this to: microsoft.publi c.vc.language

Your problem is that you are not copying the terminating null.
Try this :

int buffSize = MultiByteToWide Char(CP_ACP, 0, convertMe,
strlen(convertM e)+1, NULL, 0);
LPWSTR gah = new wchar_t[buffSize];
MultiByteToWide Char(CP_ACP, 0, convertMe, strlen(convertM e)+1, gah,
buffSize);

or, even easier:

int buffSize = (int)strlen(con vertMe) + 1;
LPWSTR gah = new wchar_t[buffSize];
MultiByteToWide Char(CP_ACP, 0, convertMe, buffSize, gah, buffSize);

Now gah will have the null-terminated Unicode string.

Dag

[Jack Klein]

On 25 Nov 2006 07:54:51 -0800, Ma************* @gmail.com wrote in
comp.lang.c++:

Hello!

I am trying to convert a char * to a LPWSTR, and I am going absolutly
mad! I can't find anything besides typle L"string" Unfortunetaly I
can't use that...

basicaly the setup is

callbackFromAno therFunctionWhi chMustBeOfChar( char* helpMe) {
//...
foo(some LPWSTR conversion);
}

this is the closest I have come to acomplishing this

char* convertMe = new char[sizeof(material s[i].pTextureFilena me)];
strcpy(convertM e,materials[i].pTextureFilena me);
wchar_t fileNameBuff[1];
int buffSize =
MultiByteToWide Char(CP_ACP,0,c onvertMe,strlen (convertMe),fil eNameBuff,0);
LPWSTR gah = (LPWSTR)new wchar_t[buffSize];
MultiByteToWide Char(CP_ACP,0,c onvertMe,strlen (convertMe),gah ,buffSize);

it converts all of the characters but I get a bunch of junk at the end
and I can't open the file.

Thanks :)

You say you can't use standard C++ features, and your code uses
non-standard, Windows specific types and API functions, all off-topic
here.

You need to ask this in a Windows group, such as
news:comp.os.ms-windows.program mer.win32.

--
Jack Klein
Home: http://JK-Technology.Com
FAQs for
comp.lang.c http://c-faq.com/
comp.lang.c++ http://www.parashift.com/c++-faq-lite/
alt.comp.lang.l earn.c-c++
http://www.contrib.andrew.cmu.edu/~a...FAQ-acllc.html

[Tim D]

Ma************* @gmail.com wrote:

>L"string" is an array of wchar_t characters.
The topical question is how to change an array of
char to an array of wchar_t.

char narrowarray[] = "Mairzy doats and dozy doats.";
wchar_t widearray[100]
mbstowcs(widea rray, narrowarray, 100);

LPSTR is a Microsoft abomination

Here Here! Thank you so much for the answer! I now have a curiosity
question if any are willing to indulge, to solve the problem i had
earlier I used

strcpy(convertM e,materials[i].pTextureFilena me);
wchar_t fileNameBuff[1];
int buffSize
=MultiByteToWid eChar(CP_ACP,0, convertMe,strle n(convertMe),fi leNameBuff,0);
LPWSTR gah = (LPWSTR)new wchar_t[buffSize];
MultiByteToWide Char(CP_ACP,0,c onvertMe,strlen (convertMe),gah ,buffSize);
/*LOOK HERE!!*/
wstring final;
for(int i = 0; i < sizeof(convertM e)*2+1;i++) {
final.push_back (gah[i]);

Can anyone tell me, why did I have to use a size of 2 + 1? It makes NO
sence at all to me, I mean I understand a wchar is twice as many bytes,
however in traversing the array does it access each part per byte
(char)? And if so then how does push_back understand it's getting char
and not wchar? Even when it's clearly being fed a wchar... I should
be able to say final.push_back (L"w"); not final.push_back "(L"w");
final.push_back (0); or whatever it be

thanks ;)

Matt

MultiByteToWide Char does not return a nul terminated C-style string, just
the converted characters. If you want a C-style string, you need to do the
bookkeeping yourself:

int buffSize = MultiByteToWide Char(
CP_ACP,
0,
materials[i].pTextureFilena me, // no need to copy the src string
-1, // -1 means src string is nul terminated
NULL, // not used when calc'ing size
0);
wchar_t gah = new wchar_t[buffSize + 1]; // translated chars plus trailing
nul
MultiByteToWide Char(
CP_ACP,
0,
materials[i].pTextureFilena me,
-1,
gah,
buffSize);
gah[buffSize] = 0; // make it a C-string

Suppose you did something like this:

char fred[]="fred";
char* newfred = new char[strlen(fred)];
strcpy(newfred, fred);

You'd blow up because you neglected to include the extra nul that strcpy
puts on the end of the string. With MultiByteToWide Char, you need to do the
strcpy-like bookkeeping yourself.