hello!!
I was looking at some code in C... and saw this "exotic" operator |=.
first time with it, what exactky does???
thanks in advance.
Erick->
37  2002 
Erick-said:
hello!!
I was looking at some code in C... and saw this "exotic" operator |=.
first time with it, what exactky does???
See K&R2, page 50.
--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999 http://www.cpax.org.uk
email: normal service will be restored as soon as possible. Please do not
adjust your email clients.
yeah, that page is about flow control but I don´t think this is the
problem. Is not flow, is assigment.
this was the line:
*cmd |= newcmd;
greetings
Erick->
Richard Heathfield wrote:
Erick-said:
hello!!
I was looking at some code in C... and saw this "exotic" operator |=.
first time with it, what exactky does???
See K&R2, page 50.
--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: normal service will be restored as soon as possible. Please do not
adjust your email clients.
Erick-wrote:
hello!!
I was looking at some code in C... and saw this "exotic" operator |=.
first time with it, what exactky does???
The lvalue on the left is inclusive-OR'd with the expression on the
right, and the result is stored in the lvalue.
:( I don't follow it
do you have a little example?? please!!!
thanks a lot!
Erick->
james of tucson wrote:
Erick-wrote:
hello!!
I was looking at some code in C... and saw this "exotic" operator |=.
first time with it, what exactky does???
The lvalue on the left is inclusive-OR'd with the expression on the
right, and the result is stored in the lvalue.
Erick-a écrit :
yeah, that page is about flow control but I don´t think this is the
problem. Is not flow, is assigment.
this was the line:
*cmd |= newcmd;
greetings
Erick->
The | operator is the bitwise OR operator. Well, in the same way the
expression x += 1; is equivalent to the x = x +1;, the above mentionned
expression is equivalent to:
*cmd = *cmd | newcmd;
Thierry
thank you!!!!
Thierry Chappuis wrote:
Erick-a écrit :
yeah, that page is about flow control but I don´t think this is the
problem. Is not flow, is assigment.
this was the line:
*cmd |= newcmd;
greetings
Erick->
The | operator is the bitwise OR operator. Well, in the same way the
expression x += 1; is equivalent to the x = x +1;, the above mentionned
expression is equivalent to:
*cmd = *cmd | newcmd;
Thierry
Erick-wrote:
Richard Heathfield wrote:
>Erick-said:
>>hello!!
I was looking at some code in C... and saw this "exotic" operator |=.
first time with it, what exactky does???
See K&R2, page 50.
yeah, that page is about flow control but I don´t think this is the
problem. Is not flow, is assigment.
this was the line:
*cmd |= newcmd;
Pleas don't top-post. I put your reply at the bottom of the
message you replied to and I kept the attribution line (the first
line: Erick-wrote: ) at the top (so everyone knows who wrote
what and in what order).
|= is like +=, -= and so on. It means that the variable
(actually, lvalue) to the left of the operator will take a value
equal to its original value bitwise-OR-ed with the value on the
right of the operator, e.g. a|=b is equivalent with a=a|b.
--
Ioan - Ciprian Tandau
tandau _at_ freeshell _dot_ org (hope it's not too late)
(... and that it still works...)
Nelu wrote:
Erick-wrote:
Richard Heathfield wrote:
Erick-said:
hello!!
I was looking at some code in C... and saw this "exotic" operator |=.
first time with it, what exactky does???
See K&R2, page 50.
yeah, that page is about flow control but I don´t think this is the
problem. Is not flow, is assigment.
this was the line:
*cmd |= newcmd;
Pleas don't top-post. I put your reply at the bottom of the
message you replied to and I kept the attribution line (the first
line: Erick-wrote: ) at the top (so everyone knows who wrote
what and in what order).
|= is like +=, -= and so on. It means that the variable
(actually, lvalue) to the left of the operator will take a value
equal to its original value bitwise-OR-ed with the value on the
right of the operator, e.g. a|=b is equivalent with a=a|b.
--
Ioan - Ciprian Tandau
tandau _at_ freeshell _dot_ org (hope it's not too late)
(... and that it still works...)
like this?
Erick-wrote:
Nelu wrote:
>Erick-wrote:
>>Richard Heathfield wrote:
Erick-said:
hello!!
>
I was looking at some code in C... and saw this "exotic" operator |=.
>
first time with it, what exactky does???
See K&R2, page 50.
yeah, that page is about flow control but I don´t think this is the
problem. Is not flow, is assigment.
this was the line:
*cmd |= newcmd;
Pleas don't top-post. I put your reply at the bottom of the
message you replied to and I kept the attribution line (the first
line: Erick-wrote: ) at the top (so everyone knows who wrote
what and in what order).
|= is like +=, -= and so on. It means that the variable
(actually, lvalue) to the left of the operator will take a value
equal to its original value bitwise-OR-ed with the value on the
right of the operator, e.g. a|=b is equivalent with a=a|b.
--
Ioan - Ciprian Tandau
tandau _at_ freeshell _dot_ org (hope it's not too late)
(... and that it still works...)
like this?
Yes, you can also snip the signatures. They don't contain any
information that is relevant to the discussion. You can also snip
other stuff that you don't think is relevant to a follow-up. Just
make sure to keep the attributions and follow-up levels untouched
(when you snip) so you don't mangle posters and follow-ups.
--
Ioan - Ciprian Tandau
tandau _at_ freeshell _dot_ org (hope it's not too late)
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