== evaluation problem

[Gary Wessle]

Hi

I ran my code in gdb after it was giving me un-expected results, to
find out why and I found where the problem is but I don't understand
why it happened.

if( username == us && password == pa ) {
cout << "connected. " << endl;
on_off = true;
} else {
cout << "wrong username or password" << endl;
}

*************** *************** *************** *************** ****
(gdb) p username
$6 = 0x805114c "sam"
(gdb) p us
$7 = 0x8051235 "sam"
(gdb) p username == us
$8 = false
(gdb) p password
$9 = 0x8051150 "jesse"
(gdb) p pa
$10 = 0x8051239 "jesse"
(gdb) p password == pa
$11 = false
(gdb) p username == us && password == pa
$12 = false
(gdb)
*************** *************** *************** *************** ****
I was expecting "True" instead of false above.

thanks

[Alf P. Steinbach]

* Gary Wessle:

>
I ran my code in gdb after it was giving me un-expected results, to
find out why and I found where the problem is but I don't understand
why it happened.

if( username == us && password == pa ) {
cout << "connected. " << endl;
on_off = true;
} else {
cout << "wrong username or password" << endl;
}

*************** *************** *************** *************** ****
(gdb) p username
$6 = 0x805114c "sam"
(gdb) p us
$7 = 0x8051235 "sam"
(gdb) p username == us
$8 = false
(gdb) p password
$9 = 0x8051150 "jesse"
(gdb) p pa
$10 = 0x8051239 "jesse"
(gdb) p password == pa
$11 = false
(gdb) p username == us && password == pa
$12 = false
(gdb)
*************** *************** *************** *************** ****
I was expecting "True" instead of false above.

It seems you're comparing pointers instead of strings.

A good solution is to use std::string.

A bad solution is to keep the raw arrays and use std::strcmp instead of ==.

--
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A: Top-posting.
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[Jim Langston]

"Gary Wessle" <ph****@yahoo.c omwrote in message
news:m3******** ****@localhost. localdomain...

Hi

I ran my code in gdb after it was giving me un-expected results, to
find out why and I found where the problem is but I don't understand
why it happened.

if( username == us && password == pa ) {
cout << "connected. " << endl;
on_off = true;
} else {
cout << "wrong username or password" << endl;
}

*************** *************** *************** *************** ****
(gdb) p username
$6 = 0x805114c "sam"

0x805114C looks like a pointer, so I'm guessing username is a char* (char
array).

You can't comapre character arrays using ==, using == on 2 character arrays
will state if the pointers are the same, which they usually won't be. If
you must use character arrays, you need to use strcmp (string compare) whice
will evaluate to 0 if the strings are 0. So:

char username[] = "John Smith";
char us[] = "John Smith";
if ( strcmp( username, us ) == 0 && strcmp( password, pa ) == 0 )
// yada yada

There is also a strncmp to cmpare n characters.

It is much better to use std::string so you don't have to do this type of
thing. Then you can use ==

std::string username = "John Smith";
std::string us "John Smith";

if ( username == us )
// yada yada

(gdb) p us
$7 = 0x8051235 "sam"
(gdb) p username == us
$8 = false
(gdb) p password
$9 = 0x8051150 "jesse"
(gdb) p pa
$10 = 0x8051239 "jesse"
(gdb) p password == pa
$11 = false
(gdb) p username == us && password == pa
$12 = false
(gdb)
*************** *************** *************** *************** ****
I was expecting "True" instead of false above.

thanks

[Gary Wessle]

"Jim Langston" <ta*******@rock etmail.comwrite s:

"Gary Wessle" <ph****@yahoo.c omwrote in message
news:m3******** ****@localhost. localdomain...

Hi

I ran my code in gdb after it was giving me un-expected results, to
find out why and I found where the problem is but I don't understand
why it happened.

if( username == us && password == pa ) {
cout << "connected. " << endl;
on_off = true;
} else {
cout << "wrong username or password" << endl;
}

*************** *************** *************** *************** ****
(gdb) p username
$6 = 0x805114c "sam"

0x805114C looks like a pointer, so I'm guessing username is a char* (char
array).

You can't comapre character arrays using ==, using == on 2 character arrays
will state if the pointers are the same, which they usually won't be. If
you must use character arrays, you need to use strcmp (string compare) whice
will evaluate to 0 if the strings are 0. So:

char username[] = "John Smith";
char us[] = "John Smith";
if ( strcmp( username, us ) == 0 && strcmp( password, pa ) == 0 )
// yada yada

There is also a strncmp to cmpare n characters.

It is much better to use std::string so you don't have to do this type of
thing. Then you can use ==

I am limited because the library provided "by Big Bucks Inc." uses
const char* username and same for password. so I have to supply the
same data type in-order to use their methods.

[Gavin Deane]

Gary Wessle wrote:

"Jim Langston" <ta*******@rock etmail.comwrite s:

It is much better to use std::string so you don't have to do this type of
thing. Then you can use ==

I am limited because the library provided "by Big Bucks Inc." uses
const char* username and same for password. so I have to supply the
same data type in-order to use their methods.

You might not be as limited as you think. If the library you are using
ever gives you a const char* you can immediately put it in a
std::string. Whenever you need to give a const char* to the library,
use the c_str() member function of std::string. You can use std::string
throughout your own code. Use of C style strings need not propogate
outside the interface to the library.

Gavin Deane

[BobR]

Gary Wessle wrote in message ...

>"Jim Langston" <ta*******@rock etmail.comwrite s:

>You can't comapre character arrays using ==, using == on 2 character

arrays

>will state if the pointers are the same, which they usually won't be. If
you must use character arrays, you need to use strcmp (string compare)

whice

>will evaluate to 0 if the strings are 0. So:

char username[] = "John Smith";
char us[] = "John Smith";
if ( strcmp( username, us ) == 0 && strcmp( password, pa ) == 0 )
// yada yada

There is also a strncmp to cmpare n characters.

It is much better to use std::string so you don't have to do this type of
thing. Then you can use ==

I am limited because the library provided "by Big Bucks Inc." uses
const char* username and same for password. so I have to supply the
same data type in-order to use their methods.

{
char bust[] = "Issimple";
char const *busted = bust;
std::string Name( bust );
std::string Name2 = busted;
cout <<"\n string Name ="<<Name<< std::endl;
cout <<" string Name2 ="<<Name2<< std::endl;
}
// out: string Name =Issimple
// out: string Name2 =Issimple

// void BigBucks( char const *dude);

BigBucks( Name.c_str() );
Now, what were you saying? <G>

--
Bob R
POVrookie